JEE Main Chapterwise PYQ: Candidates preparing for the highly competitive JEE Mains 2026 exam must check the previous year's questions. It is important to solve the JEE Mains Chapterwise PYQ to improve your score in the exam. For each subject, the entire JEE Main 2026 syllabus has been covered topic by topic with the JEE Main PYQ. Students can use the JEE Mains chapter-wise previous year questions to solve and practice efficiently. It will ensure a higher chance of scoring a good rank in JEE Mains exam. Therefore, in this article, we have mentioned the JEE Mains Chapterwise PYQ PDF download link. Let's begin.

JEE Mains PYQ Chapterwise PDF Download – Why It Matters

The JEE Mains 2026 syllabus is huge. Going through study material and trying to solve the previous years question papers all at once can be hectic. So, we have divided the material into all the chapters and added previous years question after each chapter. This technique will be very helpful as you can finish one chapter completely before moving into the next one. There are several reasons why chapterwise PYQs are important. Let's see the benefits of solving the JEE Mains chapterwise previous years questions below:

Previous year questions are very important for practicing. Practising for each chapter one at a time can help boost confidence and minimize confusion.
They will help you understand the exam pattern in a practical manner. Then you can also understand the type of questions asked from each chapter.
You will get a very good idea about the weightage and important topics as well.

JEE Main Physics PYQ chapterwise

It is very important to know which chapters to prioritize. This plan should be prepared according to the weightage of each chapter based on the previous year's weightage. Our experts have prepared the JEE Mains chapterwise weightage of all subjects based on the total number of questions asked from them in the last 10 years.

In this section, we will be seeing some of the top weighted chapters and some questions asked from them.

This table has the most important chapters of JEE Main Physics PYQ chapterwise PDF according to the last 10 years' JEE Main question papers.

Chapter Name	Weightage	Previous year Questions PDF
Optics	13.26%	Optics PYQs
Electrostatics	10.74%	Electrostatics PYQs
Properties of Solids and Liquids	9.05%	Properties of Solids and Liquids
Rotational Motion	6.53%	Rotational Motion PYQs
Magnetic Effects of Current and Magnetism	6.32%	Magnetic Effects of Current and Magnetism PYQs
Physics and Measurement	6.11%	Physics and Measurement PYQs
Atoms And Nuclei	4.84%	Atoms And Nuclei PYQs
Kinematics	4.63%	Kinematics PYQs
Thermodynamics	4.63%	Thermodynamics PYQs
Current Electricity	4.63%	Current Electricity PYQs
Oscillations and Waves	4.42%	Oscillations and Waves PYQs
Dual Nature of Matter and Radiation	4.00%	Dual Nature of Matter and Radiation PYQs
Work Energy and Power	4.00%	Work Energy and Power PYQs
Electronic devices	3.79%	Electronic devices PYQs
Electromagnetic Induction and Alternating currents	3.79%	Electromagnetic Induction and Alternating currents PYQs
Gravitation	2.74%	Gravitation PYQs
Kinetic theory of Gases	2.53%	Kinetic theory of Gases pyqs
Laws of motion	1.89%	Laws of motion PYQs
Electromagnetic Waves	1.47%	Electromagnetic Waves PYQs

JEE Main Physics PYQ

Some questions have been listed below from the top chapters:

1. Optics

Q: A convex lens of focal length 20 cm is placed at a distance of 30 cm from an object. Find the position and nature of the image formed.

Solution: Using the lens formula,

As we know,

$
\frac{1}{f}=\frac{1}{v}-\frac{1}{u}
$

Put the values in the lens formula,

$
\begin{gathered}
\frac{1}{20}=\frac{1}{v}-\frac{1}{(-30)} \\
\frac{1}{v}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60} \\
v=60 \mathrm{~cm}
\end{gathered}
$

The image is real, inverted, and formed 60 cm on the other side of the lens.

2. Electrostatics

Q: Two equal point charges +q are placed at a distance d apart. Find the electric field at the midpoint of the line joining them.

Solution: At the midpoint, the fields due to both charges are equal in magnitude and opposite in direction. Hence,

E net = 0

3. Properties of Solids & Liquids

Q:A sample of a liquid is kept at 1 atm . It is compressed to 5 atm , which leads to a change in volume of $0.8 \mathrm{~cm}^3$. If the bulk modulus of the liquid is 2 GPa , the initial volume of the liquid was $\_\_\_\_$ litre.
(Take $1 \mathrm{~atm}=10^5 \mathrm{~Pa}$ ).
Solution:

Given,
Initial pressure of liquid $\left(P_i\right)=1 \mathrm{~atm}$
Final pressure of liquid $\left(P_f\right)=5 \mathrm{~atm}$
Change in pressure $(\Delta P)=P_f-P_i=4 \mathrm{~atm}$

(Take $1 \mathrm{~atm}=10^5 \mathrm{~Pa}$ ).
Solution:
Given,
Initial pressure of liquid $\left(P_i\right)=1 \mathrm{~atm}$
Final pressure of liquid $\left(P_f\right)=5 \mathrm{~atm}$
Change in pressure $(\Delta P)=P_f-P_i=4 \mathrm{~atm}$

$
=4 \times 10^5 \mathrm{~Pa}
$

Change in volume $(\Delta V)=-0.8 \mathrm{~cm}^3$

Bulk modulus $(B)=2 \times 10^9 \mathrm{~Pa}$
Now,

$
\begin{gathered}
B=-\frac{\Delta P}{(\Delta V / V)} \Rightarrow V=-\frac{B(\Delta V)}{\Delta P} \\
\Rightarrow V=-\frac{2 \times 10^9 \times\left(-0.8 \times 10^{-6}\right)}{4 \times 10^5}=4 \times 10^{-3} \mathrm{~m}^3=4 \text { litre }
\end{gathered}
$

Hence, the answer is 4 .

4. Magnetic Effects of Current & Magnetism

Q: The percentage increase in magnetic field B when the space within a current-carrying solenoid is filled with magnesium (magnetic susceptibility

$\left.\chi_{\mathrm{Mg}}=1.2 \times 10^{-5}\right) \mathrm{is}:$
1. $65 \times 10^{-3} \%$
2. $56 \times 10^{-5} \%$
3. $56 \times 10^{-4} \%$
4. $53 \times 10^{-5} \%$

Solution:

$\begin{gathered}\% \text { change in } B=\frac{B_{\text {new }}-B_{\text {old }}}{B_{\text {old }}} \times 100 \% \\ =\frac{\mu n i-\mu_0 n i}{\mu_0 n i} \times 100 \%=\frac{\mu-\mu_0}{\mu_0} \times 100 \%=\frac{\mu_0 \mu_r-\mu_0}{\mu_0} \times 100 \% \\ =\left(\mu_r-1\right) \times 100 \%=\chi_m \times 100 \%=1.2 \times 10^{-3} \%\end{gathered}$

Hence, the answer is option (1).

5. Rotational Motion

Q: A solid sphere of mass 2 kg and radius 0.2 m rolls without slipping with a linear speed of 5 m/s. Find its total kinetic energy.

Solution:

$\begin{gathered}K_{\text {total }}=K_{\text {trans }}+K_{\mathrm{rot}} \\ K_{\text {trans }}=\frac{1}{2} m v^2 \\ K_{\mathrm{rot}}=\frac{1}{2} I \omega^2 \\ I=\frac{2}{5} m r^2 \\ K_{\text {trans }}=\frac{1}{2} \times 2 \times 5^2 \\ K_{\text {trans }}=25 \mathrm{~J} \\ K_{\mathrm{rot}}=\frac{1}{2}\left(\frac{2}{5} m r^2\right)\left(\frac{v}{r}\right)^2\end{gathered}$

$\begin{gathered}K_{\text {rot }}=\frac{1}{2}\left(\frac{2}{5} m r^2\right)\left(\frac{v^2}{r^2}\right) \\ K_{\text {rot }}=\frac{1}{5} m v^2 \\ K_{\text {rot }}=\frac{1}{5} \times 2 \times 5^2 \\ K_{\text {rot }}=\frac{1}{5} \times 50 \\ K_{\text {rot }}=10 \mathrm{~J} \\ K_{\text {total }}=K_{\text {trans }}+K_{\text {rot }} \\ K_{\text {total }}=25 \mathrm{~J}+10 \mathrm{~J} \\ K_{\text {total }}=35 \mathrm{~J}\end{gathered}$

JEE Main Chemistry PYQ chapter wise

As you already know, Chemistry is the most scoring subject in JEE Mains exam. Studying JEE Main Chemistry PYQ chapter wise PDF download will avoid confusion and help you prepare better. Let's look at some of the most important chapters in Chemistry and understand the type of questions asked.

Chapter Name	Weightage	Previous year Questions PDF
Co-ordination Compounds	8.21%	Co-ordination Compounds PYQs
Chemical Thermodynamics	6.95%	Chemical Thermodynamics PYQs
Some basic concepts in chemistry	7.79%	Some basic concepts in chemistry PYQs
Hydrocarbons	5.26%	Hydrocarbons PYQs
Organic Compounds containing Oxygen	5.26%	Organic Compounds containing Oxygen PYQs
Chemical kinetics	5.26%	Chemical kinetics PYQs
Solutions	5.47%	Solutions PYQs
Some Basic Principles of Organic Chemistry	6.32%	Some Basic Principles of Organic Chemistry PYQs
p- Block Elements	4.21%	p- Block Elements PYQs
Redox Reaction and Electrochemistry	6.11%	Redox Reaction and Electrochemistry PYQs
d - and f - BLOCK ELEMENTS	5.26%	d - and f - BLOCK ELEMENTS PYQs
Biomolecules	4.42%	Biomolecules PYQs
Atomic Structure	4.63%	Atomic Structure PYQs
Equilibrium	5.26%	Equilibrium PYQs
Organic Compounds Containing Nitrogen	3.79%	Organic Compounds Containing Nitrogen PYQs
Chemical Bonding and Molecular Structure	4.42%	Chemical Bonding and Molecular Structure PYQs
Classification of Elements and Periodic table	4.42%	Classification of Elements and Periodic table PYQs
Purification and Characterisation of Organic Compounds	2.11%	Purification and Characterisation of Organic Compounds PYQs
Organic Compounds containing Halogens	3.37%	Organic Compounds containing Halogens PYQs
Principles Related to Practical Chemistry	1.47%	Principles Related to Practical Chemistry PYQs

JEE Main Chemistry Previous Years Questions

Let's see the type of questions asked in chemistry in previous years JEE Mains exam.

1. Co-ordination Compounds

Question: Match the following:

- Co-Wilkinson catalyst

- Zn - Carbonic anhydrase

- Rh - Vitamin B12

- Mg - Chlorophyll

Solution:

- Co forms Wilkinson catalyst (Rh-based, but Co often confused in matching themes)

- Zn associates with enzyme carbonic anhydrase

- Rh is central to Wilkinson catalyst (common match)

- Mg is central in chlorophyll

2. Chemical Thermodynamics

Question: Calculate ΔG for a reaction at 298 K if ΔH=−100 kJ and ΔS=−200 J/K.

Solution:

Question: Calculate $\Delta G$ for a reaction at 298 K if $\Delta H=-100 \mathrm{~kJ}$ and $\Delta S=-200 \mathrm{~J} / \mathrm{K}$.

Solution:
Convert units: $\Delta S=-200 \mathrm{~J} / \mathrm{K}=-0.200 \mathrm{~kJ} / \mathrm{K}$

$
\begin{gathered}
\Delta G=\Delta H-T \Delta S \\
\Delta G=-100-(298 \times-0.200) \\
\Delta G=-100+59.6 \\
\Delta G=-40.4 \mathrm{~kJ}
\end{gathered}
$

3. Some Basic Principles of Organic Chemistry

Question: Which of the following statements about organic compounds is correct?

Options:

A) Organic compounds always contain metals.

B) Carbon can form four covalent bonds.

C) Organic compounds do not contain hydrogen.

D) Carbon cannot form rings.

Solution:

B) Carbon can form four covalent bonds

4. Hydrocarbons

Question: Which of the following is a saturated hydrocarbon?

Options:

A) Ethene

B) Ethyne

C) Ethane

D) Benzene

Answer:

C) Ethane

5. Organic Compounds Containing Oxygen

Question: Which functional group is present in alcohols?

Options:

A) –COOH

B) –OH

C) –CHO

D) –CO

Solution:

B) –OH

JEE Main Maths Chapter-Wise PYQ

Maths is a tricky subject. It requires a lot of practice. Your main aim in maths should be to increase speed and accuracy. Let's see the Maths most important chapters and some previous year questions. JEE Main Maths chapter-wise PYQ PDF, along with chapter-wise distribution, is given as follows:

Chapter Name	Weightage	Previous year Questions PDF
Chapter Name	Weightage	Previous year Questions PDF
Co-ordinate geometry	17.89%	Coordinate geometry PYQs
Integral Calculus	10.74%	Integral Calculus PYQs
Limit, continuity and differentiability	8.84%	Limit,continuity and differentiability PYQs
Sets, Relations and Functions	7.79%	Sets, Relations and Functions PYQs
Complex numbers and quadratic equations	6.95%	Complex numbers and quadratic equations PYQs
Sequence and series	7.37%	Sequence and series PYQs
Matrices and Determinants	7.16%	Matrices and Determinants PYQs
Statistics and Probability	6.32%	Statistics and Probability PYQs
Binomial theorem and its simple applications	4.21%	Binomial theorem and its simple applications PYQs
Three-Dimensional Geometry	5.26%	Three Dimensional Geometry PYQs
Trigonometry	4.42%	Trigonometry PYQs
Vector Algebra	4.84%	Vector Algebra PYQs
Permutations and combinations	4.21%	Permutations and combinations PYQs
Differential equations	4.00%	Differential equations PYQs

JEE Mains Maths previous Year questions:

Let's see some previous years' questions from JEE Mains Maths.

1. Co-ordinate Geometry

Q: Let A(4,−2),B(1,1) and C(9,−3) be the vertices of a triangle ABC . Then the maximum area of the parallelogram AFDE, formed with vertices D,E and F on the sides BC,CA and AB of the triangle ABC respectively, is________

Solution:

Given:

$\begin{aligned} & \mathrm{A}(4,-2), \mathrm{B}(1,1), \mathrm{C}(9,-3) \\ & \qquad \begin{aligned} & \triangle A B C=\frac{1}{2}\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right| \\ &= \frac{1}{2}|4(1+3)+1(-3+2)+9(-2-1)| \\ &= \frac{1}{2}|4 \times 4+1 \times(-1)+9 \times(-3)| \\ &= \frac{1}{2}|16-1-27| \\ &= \frac{1}{2}|-12| \\ &=6\end{aligned}\end{aligned}$

Use the property: Area of parallelogram formed on the same base and height =2×Area of triangle

So, the maximum area of the parallelogram AFDE inscribed with vertices on sides BC, CA, AB

= 2×Area of △ABC = 2×6 = 12

Hence, the answer is 12 sq. units.

2. Integral Calculus

Q: If $\int\left(\frac{1}{x}+\frac{1}{x^3}\right)\left(2 x^3-3 x^2+x^{-2}-6\right) d x=-\frac{\alpha^3}{(\alpha+1)}\left(3 x^\beta+x^\gamma\right)^{\alpha+1} \frac{1}{\alpha}+C, x>0,(\alpha, \beta, \gamma \in Z)$, where C is the constant of integration, then $\alpha+\beta+\gamma$ is equal to $\_\_\_\_$。

Solution:

$
I=\int\left(\frac{1}{x}+\frac{1}{x^3}\right)\left(3 x^{24}+\frac{1}{x^{26}}\right)^{\frac{1}{23}} d x=\int\left(\frac{1}{x^2}+\frac{1}{x^4}\right)\left(3 x+\frac{1}{x^3}\right)^{\frac{1}{23}} d x
$

Put $3 x+\frac{1}{x^3}=t \Rightarrow\left(-3 x^2-3 x^4\right) d x=d t$

$
\begin{gathered}
\Rightarrow I=-\frac{1}{3} \int t^{\frac{1}{23}} d t=-\frac{1}{3} \cdot \frac{t^{\frac{1}{23}}+1}{\frac{1}{23}+1}+C \\
=-\frac{1}{3} \times \frac{23}{24}\left(3 x-1+x^{-3}\right)^{\frac{24}{23}}+C \\
\Rightarrow \alpha=23, \beta=-1, \gamma=-3 \\
\alpha+\beta+\gamma=19
\end{gathered}
$

Hence, the answer is (19).

3. Limit, Continuity & Differentiability

Q: If $\lim _{x \rightarrow 0} \frac{\cos (2 x)+a \cos (4 x)-b x}{4}$ is finite, then $(a+b)$ is equal to:

1) 12

2) 0

3) 34

4) -1

Solution:

Given that the limit

$\lim _{x \rightarrow 0} \frac{\cos (2 x)+a \cos (4 x)-b x}{4}$ is finite,
we need to find $a+b$.

Using the Maclaurin series expansions near $\mathrm{x}=0$ :

$
\begin{aligned}
& \cos (2 x)=1-\frac{(2 x)^2}{2}+\frac{(2 x)^4}{24}+\cdots=1-2 x^2+\frac{4 x^4}{3}+\cdots \\
& \cos (4 x)=1-\frac{(4 x)^2}{2}+\frac{(4 x)^4}{24}+\cdots=1-8 x^2+\frac{32 x^4}{3}+\cdots
\end{aligned}
$

Substitute these into the numerator:

$
\cos (2 x)+a \cos (4 x)-b=\left(1-2 x^2+\frac{4 x^4}{3}\right)+a\left(1-8 x^2+\frac{32 x^4}{3}\right)-b+\cdots
$

Simplify the expression:

$
(1+a-b)+(-2-8 a) x^2+\left(\frac{4}{3}+\frac{32 a}{3}\right) x^4+\cdots
$

For the limit to be finite, the coefficients of the $x^0$ and $x^2$ terms must be zero, otherwise the numerator will not vanish at order $x^4$.

Set the constant term to zero:

$
1+a-b=0 \Rightarrow b=1+a
$

Set the coefficient of $x^2$ to zero:

$
-2-8 a=0 \Rightarrow a=-\frac{1}{4}
$

Use $a=-\frac{1}{4}$ to find $b$ :

$
b=1-\frac{1}{4}=\frac{3}{4}
$

Therefore, $a+b=-\frac{1}{4}+\frac{3}{4}=\frac{1}{2}$

Hence, the correct answer is option (1).

4. Sets, Relations and Functions

Q:The number of real roots of the equation $x|x-2|+3|x-3|+1=0$ is:

1) 4

2) 2

3) 1

4) 3

Solution: $x|x-2|+3|x-3|+1=0$
Case I: $x<2$

$
\begin{gathered}
-x(x-2)-3(x-3)+1=0 \\
-x^2+2 x-3 x+9+1=0 \\
x^2+x-10=0 \\
x=-1-\frac{\sqrt{41}}{2} \text { or }-1+\frac{\sqrt{41}}{2} \text { (rejected) }
\end{gathered}
$

1 solution

Case II: $2 \leq x<3$

$
\begin{gathered}
x(x-2)-3(x-3)+1=0 \\
x^2-5 x+8=0
\end{gathered}
$

No solution

Case III: $x \geq 3$

$
\begin{gathered}
x(x-2)+3(x-3)+1=0 \\
x^2+x-8=0 \\
x=-1 \pm \frac{\sqrt{33}}{2}(\text { no solution })
\end{gathered}
$

$\therefore x=-1-\frac{\sqrt{41}}{2}$ is the only solution

Hence, the correct answer is option (3).

5. Complex Numbers and Quadratic Equations

Q : If the set of all $a \in R \backslash\{1\}$, for which the roots of the equation $(1-a) x^2+2(a-3) x+9=0$ are positive is $(-\infty,-\alpha] \cup[\beta, \gamma)$, then $2 \alpha+\beta+\gamma$ is equal to $\_\_\_\_$

Solution:

Given the equation: $(1-a) x^2+2(a-3) x+9=0$

Let $\mathrm{f}(\mathrm{x})=f(x)=(1-a) x^2+2(a-3) x+9$

To ensure both roots are positive:

$
\begin{gathered}
D \geq 0 \\
D=[2(a-3)]^2-4(1-a)(9)=4(a-3)^2-36(1-a)
\end{gathered}
$

(i) Discriminant

$
\begin{gathered}
=4\left[a^2-6 a+9+9 a-9\right]=4\left(a^2+3 a\right) \geq 0 \\
\Rightarrow a(a+3) \geq 0 \Rightarrow a \in(-\infty,-3] \cup[0, \infty)
\end{gathered}
$

(ii) Leading coefficient (1-a) $>0 \Rightarrow a<1$
(iii) $f(0)=9>0$, always true

(iv) Vertex should lie to the left of $y$-axis:

$
-\frac{b}{a}=-\frac{2(a-3)}{1-a}>0 \Rightarrow \frac{3-a}{1-a}>0 \Rightarrow a \in(-\infty, 1)
$

Final intersection of conditions $a \in(-\infty,-3] \cup[0,1)$
This is of the form $(-\infty,-\alpha] \cup[\beta, \gamma)$

$
\begin{gathered}
\Rightarrow \alpha=3, \beta=0, \gamma=1 \\
\Rightarrow 2 \alpha+\beta+\gamma=2(3)+0+1=7
\end{gathered}
$

Hence, the answer is 7.

JEE Mains Previous years Questions

Use the links provided below to download the question papers of JEE Main:

Sr No	Paper Name
	JEE Main 2026 April Session Question Paper with Solutions
1	JEE Main 2025 January Session Question Paper with Detailed Solution
2	JEE Main 2024 (April Session) Question Papers
3	JEE Main 2024 (January Session) Question Papers
4	JEE Main 2023 (April Session) Question Papers
5	JEE Main 2023 (January Session) Question Papers
6	JEE Main 2022 (July Session) Question Papers
7	JEE Main 2022 (June Session) Question Papers
8	JEE Main 2021 (August Session) Question Papers
9	JEE Main 2021 (July Session) Question Papers
10	JEE Main 2021 (March Session) Question Papers
11	JEE Main 2021 (February Session) Question Papers
12	JEE Main 2020 (September Session) Question Papers
13	JEE Main 2020 (January Session) Question Papers
14	JEE Main 2019 (April Session) Question Papers
15	JEE Main 2019 (January Session) Question Papers
16	JEE Main 2018 Question Papers
17	JEE Main 2017 Question Papers
18	JEE Main 2016 Question Papers
19	JEE Main 2015 Question Papers
20	JEE Main 2014 Question Papers

How to Use JEE Main Chapter-Wise PYQs for Revision

Some tips for your revision are given below:

Plan your chapters out wisely.
After the completion of 3 chapters from every subject, start giving mock tests on a weekly basis.
After finishing the syllabus, plan our mock tests on a daily basis.
Keep a separate time for revision and a separate time for mock tests.
Analyze your answers in mock tests and identify your weak and strong chapters.
Strengthen and practise your weaker chapters.
Try to increase speed while solving topics that you are strong in.
Try to cover the entire syllabus so you have 2 to 3 months for only revision and solving mock tests.

How to Use PYQs for Scoring 150+ in JEE Main

It is by far the best source to improve your JEE Main score using Previous Years' Questions (PYQs). Once you figure out what the exam demands, scoring 150+ becomes much easier, and that is precisely what PYQs help you decode. It tells you the patterns of questions, concepts most repeated, and the perfect precision and quickness required for scoring well.

The smart strategy isn’t just solving PYQs but learning from them:

Learn Important Topics: These are usually the high-weightage chapters which the previous year's questions suggest, Kinematics, Chemical Bonding, Current Electricity, and Coordinate Geometry.

Trends in Questions: Find out how questions change every year. Sometimes the same concept is asked in a twisted way.

Understanding the JEE Pattern: You will actually feel how difficult it is, how questions are framed, and then some tricky distractors will be there in MCQs.

Speed & Accuracy: Time-bound practice through original papers helps you in speeding up their solutions for a gain with no loss of marks.

Constructing Exam Temperament: Solving previous years' papers gives due practice, decreases anxiety, boosts confidence, and improves decision-making in the exam.

Going through every paper thoroughly marking the errors, going through and revising less strong concepts, and practicing like problems should in itself boost your score to move beyond 150 with PYQs-difficult as starting late or going over information again could well be-but without having to study.

JEE Main PYQ Best Books

Subject	Book Name(s)	Author/Publisher
Physics	Concepts of Physics (Vol I & II)	H.C. Verma
	Fundamentals of Physics	Halliday, Resnick & Walker
	Problems in General Physics	I.E. Irodov
	Understanding Physics Series	D.C. Pandey (Arihant)
Chemistry	NCERT Chemistry (Class XI & XII)	NCERT
	Modern Approach to Chemical Calculations	R.C. Mukherjee
	Organic Chemistry	O.P. Tandon / Morrison & Boyd
	Concise Inorganic Chemistry	J.D. Lee
Mathematics	Mathematics for Class XI & XII	R.D. Sharma
	IIT Mathematics	M.L. Khanna
	Differential Calculus & Integral Calculus	Amit M. Agarwal (Arihant)
	Problems in Calculus of One Variable	I.A. Maron

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