Incline With Mass And Pulley MCQ - Practice Questions & Answers

Solve by difficulty

Two bodies of masses $\mathrm{m}_1=5 \mathrm{~kg}$ and $\mathrm{m}_2=3 \mathrm{~kg}$ are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass $\mathrm{m}_1$ will be : [Take $\mathrm{g}=10 \mathrm{~ms}^{-2}$ ]

30 N

40 N

50 N

60 N

View Solution

Assertion: One mass of 10 kg is there in an inclined plane of 30 degrees and is attached with a vertically hanging mass of 20 kg by a string; which passes over a smooth pulley; acceleration of the system is $5ms^{-2}$

Reason: acceleration of the system is $\frac{m_{2}g-m_{1}gsin\theta }{m_{1}+m_{2}}$

Assertion is true

Reason is true

Assertion and Reason both are true, And Reason is the correct explanation for the Assertion

Assertion and Reason both are false

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Concepts Covered - 1

When Block is hanging from Incline

When one Block is hanging, other is on the Incline plane.

$\begin{aligned} & a=\frac{\left[m_2-m_1 \sin \theta\right] g}{m_1+m_2} \\ & T=\frac{m_1 m_2(1+\sin \theta) g}{m_1+m_2}\end{aligned}$

Double inclined plane with different angles

$\begin{aligned} & a=\frac{\left(m_2 \sin \theta_2-m_1 \sin \theta_1\right) g}{m_1+m_2} \\ & T=\frac{m_1 m_2\left(\sin \theta_1+\sin \theta_2\right) g}{m_1+m_2}\end{aligned}$