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Projectile On An Inclined Plane - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 9 Questions around this concept.

Solve by difficulty

The time of flight of a projectile on an upward inclined plane depends upon

 

What is formula for time of flight for above case

 

In above case what is Component of acceleration along x or along inclined plane

 

in above case, what is  Component of acceleration along y or perpendicular to  inclined plane?

Concepts Covered - 1

Projectile on an inclined plane
  1. Important equations

                                 

                             U=Speed of projection

                   

$\alpha=$ Angle of projection above inclined plane (measured from horizontal line)
$\theta=$ Angle of projection above inclined plane (measured from inclined plane)
$\beta=$ Angle of inclination.
a) Initial Velocity-U

Component along x or along inclined plane $=U_x=U \cos \theta$
Component along y or perpendicular to inclined plane $=U_y=U \operatorname{Sin} \theta$
b) Final velocity $=V$

Component along x or along inclined plane $=V_x=U \cos \theta-(g \sin \beta) . t$
Component along y or perpendicular to inclined plane $=V_y=U \sin \theta-(g \cos \beta) . t$
and, $V=\sqrt{V_x^2+V_y^2}$
c) Displacement=S

Component along x or along inclined plane $=S_x=U_x t+\frac{1}{2} a_x \cdot t^2$
Component along y or perpendicular to inclined plane $=S_y=U_y t+\frac{1}{2} a_y \cdot t^2$
And $S=\sqrt{S_x^2+S_y^2}$
d) Acceleration = a

Component along x or along inclined plane $=a_x=-g \sin \beta$

    Component along y or perpendicular to  inclined plane = a_{y} = -gcos\beta

    So a=-g

 

 

2.  Important Terms
a) Time of flight

Formula

$
T=\frac{2 U \sin \theta}{g \cos \beta}
$

b) Range along incline plane

Formula

$
R=\frac{2 u^2 \cdot \sin (\alpha-\beta) \cdot \cos \alpha}{g \cos ^2 \beta}
$
 

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Projectile on an inclined plane

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