Equation Of Path Of A Projectile - Practice Questions & MCQ

A projectile is given an initial velocity of , where is along the ground and is along the vertical. If g = 10m/s², the equation of its trajectory is :

An initial velocity of $(2 \hat{i}+\sqrt{3} \hat{j}) \mathrm{m} / \mathrm{s}$ is given to a projectile, which $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. The equation of its trajectory is if $g=10 \mathrm{~m} / \mathrm{s}^2$.

A particle is moving according to the equation $y=\left(\sqrt{3} X-2 X^2\right)$. Then the horizontal range of project is