Careers360 Logo
Engineering and Architecture
Search Colleges, Exams, Schools & more
JEE Main Marks vs Percentile vs Rank 2024 - Calculate Percentile using Marks
  1. Home
  2. JEE Main
  3. Study Material
  4. Rate Law - Practice Questions & MCQ

Rate Law - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:35 AM | #JEE Main

Quick Facts

  • Rate Law is considered one of the most asked concept.

  • 61 Questions around this concept.

Solve by difficulty

QuestionEASY

Consider the reaction, 2A+B\rightarrow products. When concentration of B alone was doubled, the half­-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

View Solution

The rate law for a reaction between the substances A and B  is given by rate =  k\left [ A \right ]^{n}\left [ B \right ]^{m}.

On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

View Solution

 For the reaction,3A+2B\rightarrow C+D,  the differential rate law can be written as :

View Solution

For a reaction of the type  \mathrm{aA + bB \rightarrow products; -d[A]/dt}  is equal to

 

View Solution

 In a reaction, \mathrm{X_2 + Y_2 \rightarrow 2XY} , the X disappears at

View Solution

A reaction involving two different reactants can never be 

View Solution

Identify the correct statement for a reaction, A+ 2B→2C

View Solution
NIELIT University(Govt. of India Institution) B.Tech/ M.Tech

Last Date to Apply : 15th September | Campuses in Agartala, Aizawl, Ajmer, Aurangabad, Calicut, Imphal, Itanagar, Kohima, Gorakhpur, Patna & Srinagar

Apply
JSS University Noida Admissions 2024

170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA

Apply

During the course of a Zero order chemical reaction, the rate of a reaction

View Solution

The rate of a reaction aA +bB Products, is given by  \mathrm{k[A]^{n} [B]{^{m}}}. On doubling the concentration of A and halving the concentration of B the rate of reaction changes by 

 

View Solution
JEE Main Exam's High Scoring Chapters and Topics
This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.
Download EBook

For a chemical reaction \mathrm{ A+2 B \rightarrow C+2 D} , the initial rate  \mathrm{ -\frac{d[A]}{d t} } at  \mathrm{t=0 } is experimentally found to be  \mathrm{2.5 \times 10^{-2} \mathrm{M} \mathrm{s}^{-1} }
What is the value of \mathrm{-\frac{d[B]}{d t} }  at \mathrm{ t=0 } in  \mathrm{ \mathrm{M} \mathrm{s}^{-1} } ?

View Solution

Concepts Covered - 2

Rate Law

The rate of any reaction depends upon the concentration of the reactants in rate law equation that is rate law and rate of reaction depend upon the order of the reaction.
Let us consider this reaction:
\mathrm{xA}+\mathrm{yB} \rightarrow \text { Product }
Rate law equation for the reaction can be given as:
                            
                      \begin{array}{l}{\mathrm{R} \propto[\mathrm{A}]^{\mathrm{p}}[\mathrm{B}]^{\mathrm{q}}} \\\\ {\mathrm{R}=\mathrm{K}[\mathrm{A}]^{\mathrm{p}}[\mathrm{B}]^{\mathrm{q}}}\end{array}
\text { Order of reaction }=\mathrm{p}+\mathrm{q}
Here p, q are experimental quantities which may or may not be equal to the respective stoichiometric coefficients ( x, y).
 

Unit of Rate Constant

The differential rate expression for nth order reaction is as follows:
                       -\frac{\mathrm{dx}}{\mathrm{dt}}=\mathrm{k}(\mathrm{a}-\mathrm{x})^{\mathrm{n}}
\text { or } \quad \mathrm{k}=\frac{\mathrm{d} \mathrm{x}}{(\mathrm{a}-\mathrm{x})^{\mathrm{n}} \mathrm{dt}}=\frac{(\text { concentration })}{(\text { concentration })^{\mathrm{n}} \text { time }}=(\text { conc. })^{1-\mathrm{n}} \text { time }^{-1}
If concentration be expressed in mole L-1 and time in minutes, then
\mathrm{k}=\left(\text { mole } \mathrm{L}^{-1}\right)^{1-\mathrm{n}} \mathrm{min}^{-1}
\begin{array}{l}{\text { For zero order reaction, } \mathrm{n}=0 \text { and hence, } \mathrm{k}=\mathrm{mole} \mathrm{L}^{-1} \mathrm{min}^{-1}} \\ {\text { For first order reaction, } \mathrm{n}=1 \text { and hence, }} \\ {\: \mathrm{k}=\left(\text { mole } \mathrm{L}^{-1}\right)^{0} \min ^{-1}=\min ^{-1}} \\ {\text {For second order reaction, } \mathrm{n}=2 \text { and hence, }} \\ {\: \mathrm{k}=\left(\text { mole } \mathrm{L}^{-1}\right)^{-1} \min ^{-1}=\text { mole }^{-1} \mathrm{L} \min ^{-1}}\end{array}
The rate constant of a first-order reaction has only time in its unit. It has no concentration term in the unit. This means the numerical value of k first-order reaction is independent of the unit in which concentration is expressed. If the concentration unit is changed, the numerical value of k for a first-order reaction will not change. However, it would change with change in time.

Study it with Videos

Rate Law
Unit of Rate Constant

Study other Related Concepts

Rate Law Current Topic

Rate of Reaction
Rate Law
Order of Reaction
Zero Order Reaction
First Order Reaction
Second Order Reaction
nth Order Reaction
Methods of Determining Reaction Order
Molecularity of reaction
Pseudo First Order Reaction

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

JEE Main Articles

UP BTech Admission 2024: Round 2 Choice Filling (Started), Seat Allotment, Merit List, Counselling, Process
Sep 07, 2024
Top Engineering Exams for NIOS Candidates
Sep 07, 2024
NIRF Ranking 2024 (Out) - List of Top Engineering Colleges in India
Sep 06, 2024
NIT Warangal Cutoff JEE Main 2024 - Check here
Sep 06, 2024
JEE Main 2025 Syllabus PDF - Subject-Wise Detailed Syllabus
Sep 06, 2024
Architecture Courses After 12th - Fees, Eligibility, Duration, Top Colleges
Sep 06, 2024
JEE Main Exam Pattern 2025 - Total Marks in JEE Mains, Paper Pattern, Duration
Sep 06, 2024
Top 10 Engineering Entrance Exams in India 2025
Sep 05, 2024

B.Tech/B.Arch Admissions OPEN

NIELIT University(Govt. of India Institution) B.Tech/ M.Tech
NIELIT University(Govt. of India Institution) B.Tech/ M.Tech
Apply

Last Date to Apply : 15th September | Campuses in Agartala, Aizawl, Ajmer, Aurangabad, Calicut, Imphal, Itanagar, Kohima, Gorakhpur, Patna & Srinagar

Amity University, Noida B.Tech Admissions 2024
Amity University, Noida B.Tech Admissions 2024
Apply

Asia's Only University with the Highest US & UK Accreditation

ITM SLS Baroda University B.Tech Admissions 2024
ITM SLS Baroda University B.Tech Admissions 2024
Apply

Approved by UGC, PCI, & COA. Best Innovative Private Institute in Gujarat. 600+ Recruiters, 3000+ Students Placed, 1500+ Industrial Internship Opportunities, 250+ International Internships.

MIT Academy of Engineering B.Tech Admissions 2024
MIT Academy of Engineering B.Tech Admissions 2024
Apply

Highest CTC 25 LPA | Average CTC 5.54 LPA | 280+ Recruiters

Plastindia International University B.Tech Admissions 2024
Plastindia International University B.Tech Admissions 2024
Apply

International Learning Opportunities | UGC Approved | State-of-the-Art Laboratories

Joy University B.Tech 2024
Joy University B.Tech 2024
Apply

Outstanding faculty of Eminence from IIT, BITS, IIM, IIIT NIT, NID and faculty from foreign universities | Merit & sports based scholarship

View All Application Forms
News and Notifications
JEE Main 2025 exam date this month; updates on reduced syllabus, registration, number of attempts
September 03, 2024 - 07:24 PM IST
AP BArch Admission 2024: Registration begins today at apsche.ap.gov.in; eligibility criteria
August 12, 2024 - 11:27 AM IST
JoSAA 2024 round 4 seat allotment results out at josaa.nic.in; report online by July 15
July 10, 2024 - 07:26 PM IST
CSAB NEUT 2024 registration begins at csab.nic.in; apply by June 28
June 20, 2024 - 12:07 PM IST
Youth preparing for IIT-JEE dies by suicide by hanging himself in Rajasthan's Kota
June 16, 2024 - 03:31 PM IST
JEE Main 2024: NTA debars 39 candidates for 3 years on account of using unfair means
May 02, 2024 - 10:31 AM IST
JEE Main 2024 session 2 paper 2 answer key objection window closes today; fees
May 01, 2024 - 08:44 AM IST

Download Careers360 App's

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

  • student
    300M+

    Students

  • colleges
    36,000+

    Colleges

  • exams
    550+

    Exams

  • ebook
    1500+

    E-Books

  • certification
    16000+

    Certifications

student
Mobile Screen

We Appeared in

Joint Entrance Examination (Main)      
JEE Main 2025 Sample Papers
Back to top