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9 Questions around this concept.
Which of the following is the graph of $y=4^{-x}$?
$f(x) \rightarrow a f(x), a>1$
Stretching of a graph along the y-axis occurs if we multiply all outputs y of a function by the same positive constant (here 'a' ).
$f(x) \rightarrow \frac{1}{a} f(x)$ (a > 1)
Shrinking of a graph along the y-axis occurs if we multiply all outputs y of a function by the same positive constant (here '1/a' ).
For Example :
the graph of the function $f(x)=3 x^2$ is the graph of $y=x^2$ stretched vertically by a factor of 3, whereas the graph of $\mathrm{f}(\mathrm{x})=\frac{1}{3} \mathrm{x}^2$ is the graph of y=x2 compressed vertically by a factor of 3.
$f(x)$ transforms to $f(a x) \quad(a>1)$
Shrink the graph of $f(x)$ 'a' times along the $x$-axis after drawing the graph of $f(x)$,
$f(x)$ transforms to $f(x / a) \quad(a>1)$
Stretch the graph of $\mathrm{f}(\mathrm{x})$ ' a ' times along the x -axis after drawing the graph of $\mathrm{f}(\mathrm{x})$,
For Example: The graph of $f(x)=\sin x, f(x)=\sin (2 x)$, and $f(x)=\sin (x / 2)$.
Transformation $\mathrm{f}(\mathrm{x}) \rightarrow \mathrm{f}(-\mathrm{x})$,
When we multiply all inputs by -1 , we get a reflection about the $y$-axis
So, to draw $\mathrm{y}=\mathrm{f}(-\mathrm{x})$, take the image of the curve $\mathrm{y}=\mathrm{f}(\mathrm{x})$ in the y -axis as a plane mirror $f(x) \rightarrow-f(x):$
When we multiply all the outputs by -1 , we get a reflection about the x -axis.
To draw $y=-f(x)$ take an image of $f(x)$ in the $x$-axis as a plane mirror
For example
The graph of $y=e^x, y=-e^x \quad$ (Transformation $\left.f(x) \rightarrow-f(x)\right)$
$
f(x) \rightarrow|f(x)|
$
When $y=f(x)$ given
Leave the positive part of $f(x)$ (the part above the $x$-axis) as it is
Now, take the image of the negative part of $f(x)$ (the part below the $x$-axis) about the $x$-axis.
OR
Take the mirror image in the $x$-axis of the portion of the graph of $f(x)$ which lies below the $x$-axis
For Example:
y=x3 y=|x3| y=|x3| and y=x3
Transformation $\mathrm{f}(\mathrm{x}) \rightarrow \mathrm{f}(|\mathrm{x}|) \mid$
When $y=f(x)$ given
Leave the graph lying right side of the $y$-axis as it is
The part of $f(x)$ lying on the left side of the $y$-axis is deleted.
Now, on the left of the $y$-axis take the mirror image of the portion of $f(x)$ that lying on the right side of the $y$-axis.
For Example:
y = f(x) y = f(x) and y = f(|x|) y = f(|x|)
Transformation $\mathrm{f}(\mathrm{x}) \rightarrow|\mathrm{f}(|\mathrm{x}|)|$
First $\mathrm{f}(\mathrm{x})$ is transforms to $|\mathrm{f}(\mathrm{x})|$
Then $|f(x)|$ transforms to $|\mathrm{f}(|\mathrm{x}|)|$
Or
(i) $f(x) \rightarrow|f(x)| \quad$ (ii) $f(x) \rightarrow f(|x|) \mid$
For Example:
y = f(x) y = |f(x)| y = f(|x|)
y = |f(|x|)|
$\begin{aligned} & y=f(x) \rightarrow|y|=f(x) \\ & y=f(x) \text { is given }\end{aligned}$
Remove the part of the graph which lies below X-axis
Plot the remaining part
take the mirror image of the portion that lies above the x-axis about the x-axis.
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