UPES B.Tech Admissions 2025
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
Amplitude Modulation is considered one of the most asked concept.
86 Questions around this concept.
A signal of 5 kHz frequency is amplitude modulated on a carrier wave of frequency 2 MHz. The frequencies of the resultant signal is/are :
The wavelength of the carrier waves in a modern optical fibres communication network is close to :
A modulating signal is a square wave, as shown in the figure.
If the carrier wave is given as$c(t)=2 \sin (8 \pi t)$ volts, the modulation index is:
JEE Main 2025: Session 2 Result Out; Direct Link
JEE Main 2025: College Predictor | Marks vs Percentile vs Rank
New: JEE Seat Matrix- IITs, NITs, IIITs and GFTI | NITs Cutoff
Latest: Meet B.Tech expert in your city to shortlist colleges
A message signal of frequency 5kHz is used to modulate a carrier signal of frequency 2MHz. The bandwidth for amplitude modulation is:
The modulation index for an A.M. wave having maximum and minimum peak-to-peak voltages of 14 mV and 6 mV respectively is:
Given below are two statements :
Statement I: For transmitting a signal, the size of the antenna (l) should be comparable to the wavelength of the signal (at least in dimension)
Statement II: In amplitude modulation, the amplitude of the carrier wave remains constant (unchanged).
In the light of the above statements, choose the most appropriate answer from the options given below.
A message signal of frequency 3kHz is used to modulate a carrier signal of frequency 1.5 MHz. The bandwidth of the amplitude-modulated wave is
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
Merit Scholarships | NAAC A+ Accredited | Top Recruiters : E&Y, CYENT, Nvidia, CISCO, Genpact, Amazon & many more
Choose the correct statement :
A carrier signal $C(t)=25 \sin \left(2.512 \times 10^{10} t\right)$ is an amplitude modulated by a message signal $m(t)=5 \sin \left(1.57 \times 10^8 t\right)$ and transmitted through an antenna. What will be the bandwidth of the modulated signal?
A carrier wave of peak voltage 14 V is used for transmitting a message signal. The peak voltage (in V ) of the modulating signal given to achieve a modulation index of 80% will be :
Amplitude Modulation
The process of changing the amplitude of a carrier wave in accordance with the amplitude of the audio frequency (AF) signal is known as amplitude modulation (AM). Carrier wave remains unchanged in AM frequency. The amplitude of a modulated wave is varied in accordance with the amplitude of modulating wave.
Modulation index: The ratio of change of amplitude of carrier wave to the amplitude of original carrier wave is called the modulation factor or degree of modulation or modulation index (m).
$
\mu_a=\frac{\text { Change in amplitude of carrier wave }}{\text { Amplitude of original carrier wave }}=\frac{E_m}{E_c}
$
where
$
\mu_a=\frac{E_m}{E_c}=\frac{E_{\max }-E_{\min }}{E_{\max }+E_{\min }}
$
If a carrier wave is modulated by several sine waves the total modulated index m is given by-
$
m_t=\sqrt{m_1^2+m_2^2+m_3^2+\ldots \ldots}
$
Voluage equation for AM wave:
Suppose voltage equations for carrier wave and modulating wave are $e_c=E_c \cos \omega_c t$ and
$
e_m=E_m \sin \omega_m t=m E_c \sin \omega_m t
$
where,
The voltage equation for $A M$ wave is
$
\begin{aligned}
e & =E \sin \omega_c t=\left(E_c+e_m\right) \sin \omega_c t=\left(E_c+e_m \sin \omega_m t\right) \sin \omega_c t \\
& =E_c \sin \omega_c t+\frac{m_a E_c}{2} \cos \left(\omega_c-\omega_m\right) t-\frac{m_a E_c}{2} \cos \left(\omega_c+\omega_m\right) t
\end{aligned}
$
The above AM wave indicated that the AM wave is equivalent to the summation of three sinusoidal waves, one having amplitude ' $E$ ' and the other two having amplitude $\frac{m_o E_c}{2}$.
Sideband frequencies: The AM wave contains three frequencies, $f_c,\left(f_c+f_m\right)$ and $\left(f_c-f_m\right) . f_c$ is called carrier frequency, $\left(f_c+f_m\right)$ and $\left(f_c-f_m\right)$ are called sideband frequencies.
$\left(f_c+f_m\right):$ Upper sideband (USB) frequency
$\left(f_c-f_m\right):$ Lower sideband (LSB) frequency
In general sideband frequencies are close to the carrier frequency.
Bandwidth: The two sidebands lie on either side of the carrier frequency at equal frequency interval $\mathrm{f}_{\mathrm{m}}$.
So, bandwidth $=\left(f_c+f_m\right)-\left(f_c-f_m\right)=2 f_m$
"Stay in the loop. Receive exam news, study resources, and expert advice!"