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7 Questions around this concept.
In an optics experiment, with the position of the object fixed, a student varies the position of a convex lens and for each position, the screen is adjusted to get a clear image of the object. A graph between the object distance $u$ and the image distance $v$, from the lens, is plotted using the same scale for the two axes. A straight line passing through the origin and making an angle of $45^{\circ}$ with the $x$ - axis meets the experimental curve at $P$. The coordinates of $P$ will be
A convex lens is placed on a stand, and an object is placed at a distance of from the lens. The observer looks at the object’s image formed by the lens, which appears to be at a distance of
,on the other side of the lens. Determine the focal length ,
of the convex lens using the lens formula.
An experiment is conducted to determine the focal length of a concave lens using a lens formula. The object distance
is
, and the image distance
is
. Calculate the focal length of the concave lens.
A convex lens, of focal length 30 cm, a concave lens of focal length 120 cm, and a plane mirror are arranged as shown. For an object kept at a distance of 60 cm from the convex lens, the final image, formed by the combination, is a real image, at a distance of :
A concave mirror of radius of curvature R has a circular outline of radius r. A circular disk is to be placed normal to the axis at the focus so that it collects all the light that is reflected from the mirror from a beam parallel to the axis. For r << R , the area of this disc has to be at least
Aim-
To find the focal length of a concave lens using a convex lens.
Apparatus-
An optical bench with four upright (two fixed uprights in middle, two outer uprights with lateral movement), a convex lens (less focal length), a concave lens (more focal length), two lens holders, two optical needles (one thin, one thick), a knitting needle and a half
metre scale.
Theory-
From lens formula,
we have, $f=\frac{u v}{u-v}$
where $f=$ focal length of concave lens $L_2$
$\mathrm{u}=$ distance of I from the optical centre of lens $L_2$
$v=$ distance of I from the optical centre of lens $L_2$
(Note. According to sign convention, u and v have positive values (being measured in the direction of incident light). Since $v>u$, $u$-v is negative. Hence $f$ comes negative.)
Experiment arrangement and ray diagram-
An object needle 0 is placed on one side of a convex lens $L_1$ and its real inverted image $I$ is located (by image needle) on the other side as shown in the ray diagram.
The concave lens $L_2$ is placed between convex lens $L_1$ and image needle $I$.
The concave lens diverges the rays and the image is now formed at I' as shown in the ray diagram.
For concave lens, $I$ is the virtual object and $I^{\prime}$ is the real image. Hence, $O_2 I=u$ and $O_2 I^{\prime}=v$. Focal length can be calculated, using lens formula
$
\frac{1}{f}=\frac{1}{v}-\frac{1}{u}
$
Procedure:
To determine the rough focal length of the convex lens
1. Mount the convex lens in the lens holder.
2. Go out in the open and face the lens towards a distant tree or building.
3. Obtain the image of the tree or the building on a white painted wall (screen) and move the lens forwards and backwards to get a sharp image on the wall.
4. Measure the distance between the lens and the wall (screen). This will be equal to the rough focal length of the mirror.
To set the convex lens
5. Set the object needle
6. Set the image needle at I
7. Set the concave lens.
8. Clamp the holder with concave lens on fixed upright on the I side of the convex lens.
9. Fix this upright at some distance away from the convex lens.
10. Set the concave lens surface in the same manner as convex lens surface with principal axes of the lensescoinciding.
11. Then set the image needle at I'
12. Get more and more observations from the experiment and on the basis of observations find out the focal length of the given concave lens.
Calculations-
1. Find the difference of positions of $L_2$ and I
2. Find the difference of positions of $L_2$ and $I^{\prime}$
3. Apply index correction and write corrected value of $u$ and $v$
4. Calculate $f=\frac{u v}{u-v}$
5. Take the mean of different values of as recorded values of $f$
Mean $f=\frac{f_1+f_2+f_3}{3}=\ldots \ldots \mathrm{cm}$.
Result-
The focal length of the given concave lens $=\ldots \ldots \mathrm{cm}$
Precautions-
1. The focal length of the convex lens should be less than the focal length of the concave lens so that the combination is convex.
2. The lenses must be clean.
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