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    Principle of Mathematical Induction - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Principle of Mathematical Induction is considered one the most difficult concept.

    • 30 Questions around this concept.

    Solve by difficulty

    What can we deduce from the following mathematical expression?

    $x^2=9$

    For integers m and n, both greater than 1, consider the following three statements:
    P: m divides n
    Q: m divides $\mathrm{n}^2$
    R : m is prime,
    then

    $
    \text { If } A=\left[\begin{array}{ll}
    1 & 0 \\
    1 & 1
    \end{array}\right] \text { and } I=\left[\begin{array}{ll}
    1 & 0 \\
    0 & 1
    \end{array}\right]
    $
    then which one of the following holds for all $n \geq 1$, by the principle of mathematical induction

    Statement-1: For every natural number
    $
    n \geq 2, \frac{1}{\sqrt{1}}+\frac{1}{\sqrt{2}}+\ldots+\frac{1}{\sqrt{n}}>\sqrt{n}
    $

    Statement-2: For every natural number $n \geq 2, \sqrt{n(n+1)}>n$

    For every $n \in N \cdot 2^{3 n}-7 n-1$ is divisible by

    State True / False

    $n^3+(n+1)^3+(n+2)^3$ is divisible by $9 \forall n \in N$.

    Concepts Covered - 1

    Principle of Mathematical Induction

    Mathematical induction is one of the techniques which can be used to prove a variety of mathematical statements which are formulated in terms of n, where n is a positive integer (natural number)

    Principle of Mathematical Induction

    The statement is true for $\mathrm{n}=1$, i.e., $\mathrm{P}(1)$ is true, and
    If the statement is true for $\mathrm{n}=\mathrm{k}$ (where k is some positive integer), then the statement is also true for $\mathrm{n}=\mathrm{k}+1$, i.e., truth of $\mathrm{P}(\mathrm{k})$ implies the truth of $\mathrm{P}(\mathrm{k}+1)$.

    Then, $\mathrm{P}(\mathrm{n})$ is true for all natural numbers n .
    Property (i) is simply a statement of fact. There may be situations when a statement is true for all $\mathrm{n} \geq$ 2. In this case, step 1 will start from $\mathrm{n}=2$ and we shall verify the result for $\mathrm{n}=2$, i.e., $\mathrm{P}(2)$.

    Property (ii) is a conditional property. It does not assert that the given statement is true for $\mathrm{n}=\mathrm{k}$, but only that if it is true for $\mathrm{n}=\mathrm{k}$, then should also be true for $\mathrm{n}=\mathrm{k}+1$ for this principle to be applicable. So, to prove that the property holds, only prove that conditional proposition:

    If the statement is true for $n=k$, then it is also true for $n=k+1$.

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    Principle of Mathematical Induction

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