Careers360 Logo
ask-icon
share
    JEE Main 2026 City Intimation Slip for B.Tech Session 2 (Out); NTA JEE Exam City Allotment

    Frequency, Time Period and Angular Frequency - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 9 Questions around this concept.

    Solve by difficulty

    The graph between $|\psi|^2$ and  r ( radial distance ) is shown below.

    This represents :

    Concepts Covered - 1

    Orbital frequency

    Time Period and Frequency of Revolution of an Electron in the nth Bohr orbit

    Although the precise equations for time period and frequency of revolution are not required but still it is a good idea to look at the variations of these with the atomic number (Z) and the orbit number (n).

    We know that Time period (T) is the time required for one complete revolution and that Frequency ($\nu$) is inverse of the time period

    $\therefore T=\frac{\text { distance }}{\text { time }}=\frac{2 \pi r}{v}$

    $\because r \propto \frac{\mathrm{n}^2}{\mathrm{Z}}$ and $\mathrm{v} \propto \frac{\mathrm{Z}}{\mathrm{n}}$

    $\therefore T \propto\left(\frac{n^2}{Z} \times \frac{n}{Z}\right) \propto\left(\frac{n^3}{Z^2}\right)$

    $\therefore \nu=\left(\frac{1}{T}\right) \propto\left(\frac{Z^2}{n^3}\right)$

    It is important that you remember all the above formula and relations

    Study it with Videos

    Orbital frequency

    "Stay in the loop. Receive exam news, study resources, and expert advice!"

    Get Answer to all your questions