JEE Main and Advanced College Predictor is an AI driven tool to get the most appropriate list of college based on JEE scores. Careers360 has formulated the JEE Main college predictor and the JEE Advanced college predictor to help candidates. JEE Main and Advanced college predictor use various parameters such as previous year cutoff trends, Available seats category-wise, etc.
The most sought after institutes for engineering aspirants in India are IITs and NITs. In order to gain admission into these institutes, candidates are required to attempt and qualify in the JEE Main and JEE Advanced exams. However, it is difficult for candidates to determine which institutes they can get admission in based on their performance in the JEE Main and JEE Advanced exams.
The JEE Main and Advanced college predictors utilise the candidates scores in the JEE Main 2026 and JEE Advanced 2026 exams to predict the colleges that they have a chance of getting admission to. Candidates can use the JEE Main 2026 college predictor and JEE Advanced 2026 college predictor to decide which institutes to apply for during the JoSAA 2026 counselling.
Candidates require the following details for the JEE Main 2026 college predictor and JEE Advanced 2026 college predictor. Candidates must exercise caution while entering details into the college predictor tool as the result will be more accurate based on the accuracy of the details inputted.
Details
JEE Main college predictor
JEE Advanced college predictor
Rank
JEE Main 2026 Rank
JEE Advanced 2026 rank
Home state
Required
Not required
Caste
Gender
Disability
The steps required to use the college predictors if both JEE Main and Advanced are the same. Candidates can follow the steps below to access and use the JEE Main 2026 college predictor and JEE Advanced 2026 college predictor
Click on JEE Main college predictor (or) JEE Advanced college predictor on the Careers360 site.
Enter the CRL of JEE Main or JEE Advanced, based on the choice of exam
For the JEE Main 2026 college predictor, candidates will be required to enter the “Home state”
Enter other details such as Gender, caste and disability.
Once the details are accurately entered, click on “Predict my college”
The list of predicted JEE Main and JEE Advanced colleges will be available on the screen.
The JEE Main 2026 college predictor and JEE Advanced 2026 college predictor by Careers360 are formulated to make it easy for candidates to gain an idea of which colleges to choose during the JoSAA counselling.
Candidates will be presented with a list of colleges that they can apply for based on their JEE Main and JEE Advanced scores. This will help make informed choices during the counselling process.
Candidates will also receive information about the fees, courses available, and other facilities available in these institutes.
Candidates should also be aware of the JEE Main and JEE Advanced participating institutes while using the rank predictors.
Participating Institutes
Number of Institutes
NITs
31
IIITs
26
Other-GFTIs
38
The JEE Main and Advanced cutoffs play a major role in determining whether a candidate can enter the desired college or not, hence candidates should know the JEE Main cutoffs and JEE Advanced cutoffs.
Career360's JEE college predictor for JEE Main and Advanced is free for session 1 exam only. To access the college predictor of JEE, students needs to pay a few bucks during session 2 exam.
Yes, JEE Main and Advanced college predictor tool is the most accurate one, because we are the oldest education counselling firm where we analyse the past year's data to provide the authentic information to students in order to make a profound decision.
JEE Mains 2026 result for session 1 will be declared by February 12. For more details check
https://engineering.careers360.com/articles/jee-main-result
Below are the day-wise JEE Main session 1 questions and answers
https://engineering.careers360.com/download/ebooks/jee-main-2026-analysis-january-session
The complete analysis for JEE Main Jan 29 shift 1 exam 2026 will be updated soon at https://engineering.careers360.com/articles/jee-main-2026-january-29-question-paper-with-solutions-pdf
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-2-question-paper-with-solutions-pdf
The JEE Main Jan 28 paper for shift 1 was moderate. Although Chemistry was a bit tricky. As expected, Maths was time consuming. But Physics was on the easier side.
You can find the answers for Jan 28 shift 1 online. They are memory based. I found this article helpful
Hi Lucky, Please refer to this link and you can download the free pdf.
https://engineering.careers360.com/download/ebooks/jee-main-2026-memory-based-questions-and-analysis-of-21st-january-shift-1
625 = ms Δ T + mL 625 = m [ 125 × 300 + 2.5 × 10 4 ] 625 = m [ 37500 + 25000 ] 625 = m [ 62500 ] m = 1 100 kg M = 10 grams
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf. https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf Also, you can check ad attemp the online mock test on our platform. https://learn.careers360.com/test-series-jee-main-free-mock-test/
A general equation of a circle is
$ x^2+y^2+2 g x+2 f y+c=0 $
Since it passes through $(0,0)$,
$ c=0 $
So the equation becomes
$ x^2+y^2+2 g x+2 f y=0 $
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$ a^2+2 g a=0 $
g=-a/2
Hi Ritesh Here is the article for your reference https://hospitality.careers360.com/articles/best-books-for-nchmct-jee-preparation
Feb. 1, 2026, 8:40 p.m. IST
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