JEE Main and Advanced College Predictor is an AI driven tool to get the most appropriate list of college based on JEE scores. Careers360 has formulated the JEE Main college predictor and the JEE Advanced college predictor to help candidates. JEE Main and Advanced college predictor use various parameters such as previous year cutoff trends, Available seats category-wise, etc.
The most sought after institutes for engineering aspirants in India are IITs and NITs. In order to gain admission into these institutes, candidates are required to attempt and qualify in the JEE Main and JEE Advanced exams. However, it is difficult for candidates to determine which institutes they can get admission in based on their performance in the JEE Main and JEE Advanced exams.
The JEE Main and Advanced college predictors utilise the candidates scores in the JEE Main 2025 and JEE Advanced 2025 exams to predict the colleges that they have a chance of getting admission to. Candidates can use the JEE Main 2025 college predictor and JEE Advanced 2025 college predictor to decide which institutes to apply for during the JoSAA 2025 counselling.
Candidates require the following details for the JEE Main 2025 college predictor and JEE Advanced 2025 college predictor. Candidates must exercise caution while entering details into the college predictor tool as the result will be more accurate based on the accuracy of the details inputted.
Details
JEE Main college predictor
JEE Advanced college predictor
Rank
JEE Main 2025 rank
JEE Advanced 2025 rank
Home state
Required
Not required
Caste
Gender
Disability
The steps required to use the college predictors if both JEE Main and Advanced are the same. Candidates can follow the steps below to access and use the JEE Main 2025 college predictor and JEE Advanced 2025 college predictor
Click on JEE Main college predictor (or) JEE Advanced college predictor on the Careers360 site.
Enter the CRL of JEE Main or JEE Advanced, based on the choice of exam
For the JEE Main 2025 college predictor, candidates will be required to enter the “Home state”
Enter other details such as Gender, caste and disability.
Once the details are accurately entered, click on “Predict my college”
The list of predicted JEE Main and JEE Advanced colleges will be available on the screen.
The JEE main 2025 college predictor and JEE Advanced 2025 college predictor by Careers360 are formulated to make it easy for candidates to gain an idea of which colleges to choose during the JoSAA 2025 counselling.
Candidates will be presented with a list of colleges that they can apply for based on their JEE Main 2025 and JEE Advanced 2025 scores. This will help make informed choices during the counselling process.
Candidates will also receive information about the fees, courses available, and other facilities available in these institutes.
Candidates should also be aware of the JEE Main and JEE Advanced participating institutes while using the rank predictors.
JEE Main 2025 participating institutes
Participating Institutes
Number of Institutes
NITs
31
IIITs
26
Other-GFTIs
38
JEE Advanced participating institutes
Indian Institute of Technology Madras
Indian Institute of Technology, Delhi
Indian Institute of Technology, Bombay
Indian Institute of Technology Kanpur
Indian Institute of Technology, Kharagpur
Indian Institute of Technology, Roorkee
Indian Institute of Technology Hyderabad
The JEE main and Advanced cutoffs play a major role in determining whether a candidate can enter the desired college or not, hence candidates should know the JEE Main 2025 cutoffs and JEE Advanced 2025 cutoffs.
Career360's JEE college predictor for JEE Main and Advanced is free for session 1 exam only. To access the college predictor of JEE, students needs to pay a few bucks during session 2 exam.
Yes, JEE Main and Advanced college predictor tool is the most accurate one, because we are the oldest education counselling firm where we analyse the past year's data to provide the authentic information to students in order to make a profound decision.
Hi!
So according to your percentage that is 80 percentage in JEE Mains and a rank around 1 lakh it is difficult to get admission in CSE in BVRIT through the regular quota because cse cut offs usually goes very high.Fir ECE your chance of getting admission is very less but not impossible if you are OBC/SC/ST. You can also apply through management quota but the fees will be higher.
I think you want to say 86 percentile because JEE Mains releases merit lists based on percentile, not percentages. So, with this percentile, you can get into several government colleges or private colleges in the city of Hyderabad. There many colleges in hyderabad that accept mains score, some popular ones arfe
But there are several colleges in this rank, which you can check with our college predictor in this link from Career360:
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp
Hello,
There is good news for you. You can get admission to the JECRC Foundation for the B.Tech program with just 12th marks. They can give you admission without a JEE Mains score; they just need your 12th marks, and based on this merit, you can obtain a seat in this institute. While you have 90.20% in your 12th, so it's a strong merit from your end. There is a high possibility that you will get admission to JECRC Foundation.
I hope it's clear your query!!
With 88 percentile in JEE Mains, chances for CS/ECE/EEE in top NITs or IIITs are low. However, you may get these branches in private universities like Amity, Sharda, Galgotias, or lower-tier state government colleges through state counselling.
Hello aspirant,
The syllabus of JEE MAINS PAPER 2A for degree B.Arch inculdes three subjects: maths, aptitude test, and drawing.
The exam is of 400 marks with 77 questions and of 3 hours. -1 negative marking will be given for every wrong answer of maths or numerical value question. For drawing test, there will be no negative marking.
There are many platforms online providing sample papers, one of which is careers360. The link of which, I am attaching here,
https://engineering.careers360.com/articles/jee-main-syllabus-2026
Best of luck for your preparation.
Hello
NIT Kurukshetra – Civil Engineering (JEE Main Cut-offs)
2024 Round 3 and 4 Final Closing Ranks
All India (AI Other State) Category – Gender Neutral
Opening Rank: Approximately 15,535
Closing Rank: Around 29,292 in Round 1, and up to 33,266 by Round 4
Home State (HS Haryana) Category – Gender Neutral
Opening Rank: Approximately 9,853
Closing Rank: Around 38,638 across various rounds
Expected Cut-Offs for 2025 (Projected)
The estimated closing ranks for Civil Engineering in the early rounds are as follows:
All India (Open): Between 15,520 and 34,638
EWS (All India): Between 4,090 and 46,628
OBC NCL (All India): Between 7,946 and 12,000
SC (All India): Between 1,445 and 5,155
ST (All India): Between 960 and 1,136
Note: These expected cutoffs are only estimates based on previous year trends and are subject to change depending on this year's exam and counselling dynamics.
Dear candidate , Cutoffs for JEE Main 2024 for Tatyasaheb Kore Engineering college ( TKIET ) . Warananagar : - CSE : 65,000 ( All India ) , 36,000 ( Home state ) . - Electronics and Telecom : 40,000 - Chemical Engineering : 47,000 . - Cyber security : up to - 85,000 .
Hello Srinidhi,
In order to acquire Mechanical Engineering at NIT Kurukshetra, generally the required JEE Main rank will be in the range of:
The cutoffs that I have provided above change from year to year, as well as category and gender. For reserved categories (SC/ST/OBC/EWS), the ranks are much more relaxed.
For JEE Main 2024, the closing ranks at Rajarambapu Institute of Technology, Islampur (General category, All India) were approximately:
Computer Engineering: 2,10,000 – 2,40,000
CSE (AI/ML or IT): 2,30,000 – 2,80,000
Electronics & Telecommunication: 3,60,000 – 3,85,000
Electrical Engineering: 4,70,000 – 4,80,000
Civil Engineering: 4,15,000 – 4,85,000
Mechanical Engineering: 6,05,000 – 6,15,000
Robotics & Automation: 5,50,000 – 6,00,000
These are approximate ranges based on Round 3 or final round cutoffs. Some variation can occur based on seat availability and category.
As per your query, the JEE rank required for NIT Kurukshetra in Computer Science Engineering branch is,
All India Closing Rank (General category) : 6562
Home state Closing Rank (General category) : 8198
For more information, click on the link given below,
https://www.careers360.com/university/national-institute-of-technology-kurukshetra/cut-off
Regards
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