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HSTES College Predictor 2025: The careers360 HSTES college predictor 2025 is a special tool that can help students get admission through HSTES Counselling this year. Further, this tool identifies the most appropriate engineering colleges for students depending on their JEE Main score, or any state-level entrance test. Candidates can enter their rank, category, etc, and get an idea of the colleges they might be getting into with previous years' admission data. The HSTES College Predictor provides valuable information such as placements, branch/college-wise cut-offs & rankings of the colleges. Secondly it helps students make the right choices regarding the college they’ve decided to study at. It’s easy to ‘nudge’ students towards different colleges, showing them what their home college looks like, what it would look like in their sphere of influence, and where it fits within the bigger picture. HSTES 2025 helps in preparing for the Counselling process and increases your chances of joining any University to pursue college.
The HSTES 2025 College Predictor is a great aid for all those students who want to seek admission to Engineering and technical institutions of Haryana through the HSTES entrance exam. After entering their ranks and relevant details, students can receive tailored predictions based on which colleges and courses they are suitable for. This predictor does not only produce a list of the relevant colleges but also provides other relevant data concerning the colleges, such as rankings, feedback, cutoffs, and any other significant information, to the students.
Candidates are advised to follow the below-mentioned steps to use the HSTES College Predictor 2025:
Select the right counselling process for admission.
Please enter your overall percentile rank of an applicant in the JEE Main Examination.
Select your home state and mention your caste also.
Choose your gender and if you are specially-abled, please tick the box.
Click on the ‘Predict My College’ tab
The list of colleges will be displayed on the screen.
Includes recommendations based on your specific rank.
Gives information about ranking, rating, and cut-off mark indicators for each college.
Easy to use hence accommodating all the students in the class.
Students make the right choices to make for their educational endeavours.
Offers a list of suitable colleges, saving time that would otherwise be spent researching.
Provides information about colleges where the students are most likely to gain admission based on their ranks.
S. No.
Name of the Institute
1
Ch. Devi lal State Institute of Engineering & Technology, Panniwala Mota
2
Ch. Ranbir Singh State Institute of Engineering & Technology, Silani Kesho (Jhajjar)
3
Rao Birender Singh State Institute of Engineering & Technology, Zainabad (Rewari)
4
State Institute of Engineering & Technology, Nilokheri
5
J.C. Bose University of Sci. & Technology, YMCA, Faridabad
6
Guru Jambheshwar University of Science & Tech. Hisar
7
Ch. Charan Singh HAU, Hisar
8
University Institute of Engg. & Technology, MDU Rohtak
9
DBCR University of Science & Technology Murthal
10
School of Engineering & Sciences, BPS Mahila Vishwavidyala, Khanpurkalan
11
Kurukshetra University, Kurukshetra
Hi!
So according to your percentage that is 80 percentage in JEE Mains and a rank around 1 lakh it is difficult to get admission in CSE in BVRIT through the regular quota because cse cut offs usually goes very high.Fir ECE your chance of getting admission is very less but not impossible if you are OBC/SC/ST. You can also apply through management quota but the fees will be higher.
I think you want to say 86 percentile because JEE Mains releases merit lists based on percentile, not percentages. So, with this percentile, you can get into several government colleges or private colleges in the city of Hyderabad. There many colleges in hyderabad that accept mains score, some popular ones arfe
But there are several colleges in this rank, which you can check with our college predictor in this link from Career360:
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp
Hello,
There is good news for you. You can get admission to the JECRC Foundation for the B.Tech program with just 12th marks. They can give you admission without a JEE Mains score; they just need your 12th marks, and based on this merit, you can obtain a seat in this institute. While you have 90.20% in your 12th, so it's a strong merit from your end. There is a high possibility that you will get admission to JECRC Foundation.
I hope it's clear your query!!
With 88 percentile in JEE Mains, chances for CS/ECE/EEE in top NITs or IIITs are low. However, you may get these branches in private universities like Amity, Sharda, Galgotias, or lower-tier state government colleges through state counselling.
Hello aspirant,
The syllabus of JEE MAINS PAPER 2A for degree B.Arch inculdes three subjects: maths, aptitude test, and drawing.
The exam is of 400 marks with 77 questions and of 3 hours. -1 negative marking will be given for every wrong answer of maths or numerical value question. For drawing test, there will be no negative marking.
There are many platforms online providing sample papers, one of which is careers360. The link of which, I am attaching here,
https://engineering.careers360.com/articles/jee-main-syllabus-2026
Best of luck for your preparation.
Hello
NIT Kurukshetra – Civil Engineering (JEE Main Cut-offs)
2024 Round 3 and 4 Final Closing Ranks
All India (AI Other State) Category – Gender Neutral
Opening Rank: Approximately 15,535
Closing Rank: Around 29,292 in Round 1, and up to 33,266 by Round 4
Home State (HS Haryana) Category – Gender Neutral
Opening Rank: Approximately 9,853
Closing Rank: Around 38,638 across various rounds
Expected Cut-Offs for 2025 (Projected)
The estimated closing ranks for Civil Engineering in the early rounds are as follows:
All India (Open): Between 15,520 and 34,638
EWS (All India): Between 4,090 and 46,628
OBC NCL (All India): Between 7,946 and 12,000
SC (All India): Between 1,445 and 5,155
ST (All India): Between 960 and 1,136
Note: These expected cutoffs are only estimates based on previous year trends and are subject to change depending on this year's exam and counselling dynamics.
Dear candidate , Cutoffs for JEE Main 2024 for Tatyasaheb Kore Engineering college ( TKIET ) . Warananagar : - CSE : 65,000 ( All India ) , 36,000 ( Home state ) . - Electronics and Telecom : 40,000 - Chemical Engineering : 47,000 . - Cyber security : up to - 85,000 .
Hello Srinidhi,
In order to acquire Mechanical Engineering at NIT Kurukshetra, generally the required JEE Main rank will be in the range of:
The cutoffs that I have provided above change from year to year, as well as category and gender. For reserved categories (SC/ST/OBC/EWS), the ranks are much more relaxed.
For JEE Main 2024, the closing ranks at Rajarambapu Institute of Technology, Islampur (General category, All India) were approximately:
Computer Engineering: 2,10,000 – 2,40,000
CSE (AI/ML or IT): 2,30,000 – 2,80,000
Electronics & Telecommunication: 3,60,000 – 3,85,000
Electrical Engineering: 4,70,000 – 4,80,000
Civil Engineering: 4,15,000 – 4,85,000
Mechanical Engineering: 6,05,000 – 6,15,000
Robotics & Automation: 5,50,000 – 6,00,000
These are approximate ranges based on Round 3 or final round cutoffs. Some variation can occur based on seat availability and category.
As per your query, the JEE rank required for NIT Kurukshetra in Computer Science Engineering branch is,
All India Closing Rank (General category) : 6562
Home state Closing Rank (General category) : 8198
For more information, click on the link given below,
https://www.careers360.com/university/national-institute-of-technology-kurukshetra/cut-off
Regards
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