Hi there,

Hope you are doing fine.

The specific number of seats available in each category for the Mathematics department at NERIST (North Eastern Regional Institute of Science and Technology) through the NEE-3 (NERIST Entrance Examination)  may vary each year based on several factors including the changes in the policy and demand, the number of seats available and the number of applicants.

To get accurate and detailed information about seat distribution by category (such as General, OBC, SC, ST, and others) it is best to refer to the official NERIST admission brochure for the current academic year or visit their official website.

You can also contact the NERIST admissions office directly for the most recent and precise details regarding seat allocation. This will ensure that you receive the most reliable information relevant to the specific year and category you are interested in.

Hope this resolves your query.

Dear aspirant !

Hope you are doing well !

Yes definitely it is possible to apply if you don't have debit card . You can pay by using other UPI or banking methods ,debit card is not a necessity,many other options are available nowadays. We are living in a generation where all the things are available . So don't worry about that . Just go for apply .

Hope it helps you !

Thank you !

Hello candidate,

Here is the list of some of the important formulas for JEE mains examination-

1. The energy of electric dipole is given by U = – p.E.

2. The energy of a magnetic dipole is U = – μ .B C.

3. Electrostatic Force (F) = k[q1q2/r2]

4. Resistivity : ρ(T)=ρ(T0)[1+α(T−T0)]

R (T) =R (T0) [1+α (T−T0)

5. Magnetic Flux through Area dS = =→B⋅d → S= B⋅dS Cos θ

6. Gravitational force →F=G[Mm/r2]^r

7. Work Done (W) = →F⋅→S=→F →S cosθ

8. Boyle’s Law: P1V1 = P2V2 (at constant T and n)

9. Charles’s Law: V1/ T1 = V2/ T2 (at constant P and n)

10. Enthalpy: H = U + pV

11. First Law of Thermodynamics: ΔU = q + W

12. Ohm’s Law: V = RI where, R = ρ ι/a

13. Standard quadratic form-

• ax^2 + bx + c = 0
• Sum of roots = -b/a,
• Product of roots discriminate = b^2 – 4ac
• If α, β are roots then Quadratic equation is x^2 – x(α + β) + αβ = 0
• Number of terms in the expansion: (x+a)n is n+1

14. Cube roots of unity are: 1, ω, ω2|z1+z2|<=|z1|+|z2|; |z1+z2|>=|z1|-|z2|; |z1-z2|>=|z1|-|z2|

Hope you found it helpful!!

Hello,

JCECEB means Jharkhand Combined Entrance Competitive Examination Board is the conducting authority for Jharkhand NEET, the online application form for the same had already been released on 19th January at the official website at https://jceceb.jharkhand.gov.in (https://jceceb.jharkhand.gov.in/IMP_l/826.pdf) , the last date to fill in the application form was 26th January, provisional merit list was released on 30th January, final merit list was released on 2nd February, the counselling process for round is over, and the registration for second round commenced on 15th and last date was 17th, the provisional merit list for round 2 is to be out by 20th February, final merit list will be published by 24th February, online registration for round 2 and choice filling will begin by 25th February till 1st March, seat allotment/download of the provisional allotment letter/document verification/reporting to the designated college will be from 5th March to 9th March, check out the entire schedule of round 2 at https://jceceb.jharkhand.gov.in/IMP_l/826.pdf, for round 1 you can visit at https://jceceb.jharkhand.gov.in/con_notice/508.pdf

Dear Reader,

Hope you are doing well...

In this year, there is no correction window offered by any state for NEET counselling registration.As due to tight schedule of counselling for NEET this year,they did this.But seems like in future they provide any chances of correction or any alternate regarding this as many candidates face this problem.So,after managing tight schedule of counselling they can offer any alternate regarding the correction.So,you should always keep yourself update regarding the correction as any time they put any notification regarding this.

Hope above information helps you to clear your doubts regarding this.

Hace a good day and great future ahead..

Dear Candidate, admission in Delhi University is based on the percentage of your best 4 subjects not in one particular subject.

Here's attaching a link for your help.

https://university.careers360.com/delhi-university-college-predictor?utm_soource=qna&utm_medium=du_cp

All the best for the future!