Joint Entrance Examination (Main)
Considering the rank formula( "864469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 864469 / 100"), your rank will be be around 67-70k. So with this rank you are pretty safe with your qualification.
With 99.59 percentile, you can get an estimated CRL Rank of 3,500. This has been calculated by using the formula: (100-99.59)*869010/100 = probable rank. With this rank and the EWS Quota, you can easily get into all of the top NITs, be it NIT Trichy, Warangal or Suratkal. Talking about branch now, you can easily get ECE and CSE both in all of the top NITs, so you can focus on your JEE Advanced now. For more details on the colleges that you can get, use this college predictor -
Congrats on the percentile and all the best.
Hi akanksha singh,
The top 5 B.Tech colleges which are accepting upsee exam scorecard are:
1. Harcourt Butler Technological Institute (HBTI), Kanpur: It is the North India’s best engineering colleges, also HBTI is one of the country’s oldest scientific institutions. HBTI offers UG ,PG and doctoral programmes in engineering, and computer applications. These courses are accredited and approved by NAAC and AICTE. For CSE Branch the closing rank of HBTI is 5328. The fee per annum for B.Tech is 53,000.
2. Institute of Engineering and Technology, Lucknow: The campus is spread across 100 acres. The specializations offered in B.Tech are ECE,CSE,CE,ME,Chemical Engg., EEE.. The annual fee for B.Tech is Rs. 31,000. The cutoff rank for CSE goes from 209 - 937 rank.
3. Kamla Nehru Institute of Technology (KNIT), Sultanpur: The college was founded in 1976 by the Kamla Nehru Memorial Trust. The course fee for Bachelor of Technology is Rs. 59,600 per annum. The opening and closing rank for Computer Science and Engineering is 1271- 2134.
4. Madan Mohan Malviya Engineering College, Gorakhpur: MMM offers most of its courses in technical fields of engineering. The course fee for B.Tech is Rs. 76,800. And the opening and closing rank for CSE is in between 1321- 2564.
For more information visit the link given below:
Yes,you can apply for jee mains and you are eligible for mains. Since you cleared your 12th it is not anymore problem. And you cleared it with 78%. Yes,you can apply for jee mains. All the best for JEE mains. Prepare well. Do hardwork. Work until you achieve it. Good luck. If you are qualified for Jeemains then you will be eligible to write jee advanced.
On basis of your jee mains score and 12 th board percentage you can get Admission to various colleges through reap which is rajasthan engineering admission process.
basically you to apply for reap through official website of reap .Then you have to fill form and fill preferenves .Then you can fill colleges which are affiliated to Rajasthan Technical University Kota .The private colleges such as Jecrc,Poornima colleges of engineering,Swami keshvanand Institute of technology are under affiliation of Rajasthan Technical University.
If you want more information about reap then you can follow the link mentioned below
All the very best
It is good that you got 78 percentile. But it is not enough to qualify for advanced for general category students. This year approximate cut off for general students is 80 percentile. Don't worry. Work hard for coming exam. Give extra hard work for the topics you are weak. If you do so, you can gain good marks. You have a chance in april use it well and write well. All the best. Good luck. Work Hard.
You have to give your best to score good .You have to just denote consitent hours to study for months .Just preparation from today and try to cover the topics which are comfortable for your and contains maximum weightage.Read Ncert in depth and prepare short notes for it .
Solve all the questions papers of jee mains of all shifts and analyse them for better score.
Practice lot and attempt question efficiently it means Try to solve question in minimum time .
If you want to know further about Jee Mains April session then you can visit the link mentioned below
The formula to calculate rank is given by national testing AGENCY.The formula is
No of candidates apperared/100*(100- Nta score).So as per january session
candidates appeared for Jee mains session .
So your rank will be around 66566
But if no of candidates in April session changes to
then rank can vary accordingly.
If you want to know about colleges in which you have chances of getting Admission then you can visit the link mentioned below
ALL the very best
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