Hello

Indian Institutes of Science Education and Research (IISER) will conduct IISER 2019 admission for 5-year BS-MS degree programmes at its seven participating institutes. IISER admission 2019 will be conducted through three channels- KVPY, SCB and JEE.

Candidates opting for admission through KVPY and JEE are eligible for direct admission and an aptitude test will be conducted for students who opt for SCB channel.

Check the detailed information using the link below-

 https://engineering.careers360.com/articles/iiser-admission

Good Luck!

Hello,

You can download some model papers of IISER from the link given below

https://engineering.careers360.com/articles/iiser-2016-sample-papers

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All the best for your examination.

Yes IISER follow the following reservation Policy

 As per Government of India rules. SC — 15%, ST — 7.5%, OBCNC — 27%, PD — 5% (supernumerary) and KM – 3 seats per IISER (supernumerary).

Where supernumerary seats are extra seats created for a reserved category without affecting the original seats, and KM means Kashmiri Migrants.

hello vikas,

i think there are 3 channels for iiser,namely scb,jee,kvpy channels.

i suggest you to know the eligibility criteriae of iiser to go through the given link,

https://engineering.careers360.com/articles/iiser-admission

copy it and paste it in the address bar of your browser.

I Hope this information will be useful to you.

if you need additional information,let us know to help you.

Thank you!!!:)

 Magnitude of Sum of Two vectors Vector P and Vector q is given by

R^2 =p^2+q^2+2pqcos($)   __________________________(i)

Here $ indicates angle between them.

We are given 

R=p+q

So Squaring  both the sides we  get

R^2=p^2+q^2+2pq    ______________________(ii)

From (i) and (ii) we can write

P^2+q^2+2pqcos($)=p^2+q^2+2pq

Therefore 2pq=2pqcos($)

Cos($)=1

Therefore $=0

So angle between p vector and q vector is 0 degree.

 Magnitude Sum of Two vectors Vector P and Vector q is given by

r^2 =p^2+q^2+2pqcos($)   __________________________(i)

here $ indicates angle between them.

We are given 

r=p+q

so Squaring  both the sides we  get

r^2=p^2+q^2+2pq    ______________________(ii)

From (i) and (ii) we can write

p^2+q^2+2pqcos($)=p^2+q^2+2pq

therefore 2pq=2pqcos($)

cos($)=1

therefore $=0

So angle between p vector and q vector is 0 degree.

Hello

Admission to degree programme in IISER is done through three channels- KVPY, SCB and JEE Advanced. 

You can go through the link below to check the detailed information. 

 https://www.iiseradmission.in/

Good Luck!

if you choose kvpy for getting into iiser then it will definitely affect your admission.but there are other exams too.for details you can refer below link:

• https://engineering.careers360.com/articles/iiser-admission      I Hope this information will be useful to you.if you need additional information,let us know to help you.Thank you!!!:)

If you passed your 12th board with in science stream in the year 2017 or 2018 then yes, you can apply and give test for IAT this year. minimum percentage required is 55% for SC,ST and KM caategory students and for remaining categories minimum requirement is state cutoff.

Fee for general and OBC - INR 2000

fee for other categories - INR 1000

All the Best!