Saveetha Engineering College Chennai Commences B.Tech Admission 2019
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Saveetha Engineering College B.Tech Admission 2019 - Saveetha Engineering College (SEC), Chennai has started the application cum admission procedure for B.Tech programme for the Academic year 2019-21. The application form is available in online mode only. Interested students are advised to check the eligibility criteria before filling the application form. Candidates have to submit the online application form on or before the last date. After that, the link will be closed automatically. SEC B.Tech admission 2019 will be done on the basis of the qualifying exam marks.

To apply for Saveetha engineering College B.Tech Admission 2019- Click here

Overview of Saveetha Engineering College Tech Admission 2019

Particulars

Details

College name

Saveetha Engineering College (SEC)

Course

B.E/B.Tech

Duration

Full Time- Four Years

Course Fee

Rs. 1.80 Lakhs

Mode of Application

Online

Streams

  • Agriculture Engineering

  • Biomedical Engineering

  • Civil Engineering

  • Chemical Engineering

  • Computer Science & Engineering

  • Electronics & Communication Engineering

  • Electrical & Electronics Engineering

  • Electronics & Instrumentation Engineering

  • Information Technology

  • Mechanical Engineering

  • Medical Electronics

Eligibility Criteria

  • He/She should have passed the Higher Secondary Examination of (10 +2) Curriculum (Academic Stream) prescribed by the Government of Tamil Nadu with Mathematics, Physics and Chemistry as three of the four subjects of study under Part-III or any examination of any other University or authority accepted by the Syndicate of Anna University of Technology Chennai as equivalent thereto.

  • He/She should have passed the Higher Secondary Examination of Vocational Stream (Vocational groups in Engineering / Technology) as prescribed by the Government of Tamil Nadu.

Admission Criteria

  • Based on the cut off marks obtained in the higher secondary (10+2) examination or Should have passed the higher secondary examination of Vocational stream (Vocational groups in Engineering/ Technology) as prescribed by the Govt. of Tamilnadu through the Single Window Counseling allotted by Anna University through Tamilnadu Engineering Admissions (TNEA) & Consortium of Self Financing Professional, Arts and Science Colleges in Tamilnadu.

  • Cut off mark = 200 (100 for Mathematics and 100 for Physics + Chemistry)

About SEC

Saveetha Engineering College was started in the year 2001 by the Saveetha Medical & Educational Trust, is committed to developing this college into a renowned institution for Engineering education and research. The Saveetha Group of Institution is headed by Dr. N. M. Veeraiyan, a committed and dedicated Medical Professional.

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Address & Contact Number

Telephone: 91 44 66726690 / 66726603 / 66726604

E-mail: admission@saveetha.ac.in

Address: Saveetha Nagar, Thandalam, Chennai - 602 105, Tamilnadu, India.

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Questions related to Saveetha Engineering College, Chennai

Showing 138 out of 138 Questions
5 Views

the amplitude of a particle in shm is 5cms and iths time period is pie at a displacement of 3 cms Fromm iths mean position the velocity in cms sec willbe

Rakesh Sai 9th Dec, 2019
Hey ..
I think the formula for velocity of a particle in SHM is
Velocity = omega ( amplitude - displacement )
So the answer for the given terms would be
V = w (a-x)
w= 2/T.     where T is time period
w= 2 rad /sec
a = 5 cm
x = 3 cm
So V = 8 cm/sec
Hope the answer is right...
All the best..
7 Views

yesterday IEO result has been declared.my daughter is reading in class2 sec.A scoring 20 and got the rank 4 in school.her friend is reading also in class 2 sec.B scoring 17 and got the rank 3 in school.both are the student of KVNo.2 balangir,odisha.how is it possible sir?

Drut 5th Dec, 2019
Hello poonam
It is good to hear that your daughter is taking part in olympiads from such a little age. There are some factors which affect the rank in these olympiads, one of them is alphabetic order of the name. Also, sometimes there is some mistake in the omr that gets neglected. I'd say don't take stress because she's at a very tender age and you should just motivate her instead of comparing her with other students.
13 Views

How can i find 1 to 360 degree for sin ,cos tan, cosec, sec, cot, (theta)???

Devraj choudhary Student Expert 15th Nov, 2019

Hii

Finding the trignometric function values for all angle is very difficult.  You need to first remember the standard ones like 0,30,45,60,90. And then you can use some trignometric formulas to calculate some other angles like 15,75 etc.. Finding every angle manually is very difficult.

Hope it helps

13 Views

a particle starts with some initial velocity and constant acceleration in some direction.distance travelled by the particle in first 4 sec is 100 m and in next 4 sec is 140m. find velocity of the particle at 6 second?

Rishi Garg 30th Nov, 2019

Using s = ut + 1/2a(t^2),  we can write

100 = 4u  + 8a

=> u + 2a = 25             ------(1)

Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write

240 = 8u + 32a

=> u +4a = 30              ------(2)

Solving Eq.1 and 2 we can say,

a = 5/2 m/s/s and u = 20 m/s

Hence the velocity at t=6 sec, is 20 + 5/2*6 = 35m/s.

6 Views

how to control anger.......i have more anger...with in sec i will get...with that i am getting problems plzz help me

Vishwaksen Gouda Student Expert 22nd Sep, 2019
Hloo jahnavi,
So you are having problem with your angryness.Its so simple that when you get angry with one person you have to remember the happy times that you spent with that person.Its enough or else consult a psychiartist and tell about your problem then he will give the better solution than me.
Thank you
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