JEE Advanced to come under NTA? MHRD sends proposal to IIT Council
Prabha Dhavala, 28 Nov 2017, #JEE Advanced
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The Ministry of Human Resource and Development, MHRD has reportedly approached the IIT Council which is the regulator for all IITs to consider the conduction of the JEE Advanced by the National Testing Agency. It may be remembered that the Prime Minister along with the cabinet had approved the setting up of the National Testing Agency on November 10, 2017 with the sole purpose of conducting all the competitive entrance exams pertaining to higher education in the country that were otherwise being conducted by the CBSE.

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The MHRD has written to the IIT Council to consider its suggestion of bringing even the JEE Advanced under the ambit of the National Testing Agency along with the other entrance exams that are to be conducted by the agency like the JEE Main which is also the eligibility test for the JEE Advanced. It is reported that the MHRD has also approached the IIMs with a similar proposal for CAT such that the NTA becomes the testing agency in all respects for all the higher education entrance exams. MHRD has reportedly asked the IITs as well as the IIMs to send their responses by December 15.

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The National Testing Agency is being set up under the Indian Societies Registration Act, 1860 and will act as the autonomous and self-sustained premier testing organization with the sole jurisdiction of conducting the relevant entrance exams for admissions to higher educational institutions. The agency will be for a start conducting the entrance exams that were earlier conducted by CBSE like the JEE Main, NEET, National Eligibility Test, Central Teacher Eligibility Test as well as the entrance test for the Jawahar Navodaya Vidyalayas to name a few.  It is proposed that these exams may be conducted twice a year to aid students and allow them the choice of the better of the two scores for admission purposes. This is to ensure that CBSE which is relatively burdened otherwise to concentrate on improving the quality of education. Check details here

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IITs are reportedly not convinced or happy about the proposal to allow JEE Advanced under the aegis of the National Testing Agency. The general consensus is that the NTA has just been set up and is relatively new. Therefore it is not as equipped to hold an important exam like the JEE Advanced as it has very little operational experience. However the concerned officials are expected to revert to this proposal by December 15. More clarity on this matter will be available after this date.

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Questions related to JEE Advanced

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11 Views

i passed class 12 in 2018 but given improvement in 2019 can i give jee advance and get admission in iit in 2020? is their any way so that i get admission in iit for btech?

Manidipa Kundu Student Expert 7th Dec, 2019
hi,
as you have passed 12th exam on 2018 , the passing year will considered as 2018. the improvement exam year is not consider for 12th passing year.
so for 2020 jee advance exam you are not eligible.
4 Views

lowering of vapour pressure of equimolar solution of glucose,sodium chloride and barium nitrate are in the order

prem meghani 7th Dec, 2019
Dear Aspirant,

Vant Hoff factor =i
For Barium nitrate,i=3,
2Ba+ No3-

For Nacl,i=2Na+ Cl-
i=2 vant Hoff factor

For glucose vant Hoff factor will be 1
I=1

So higher the vant Hoff factor higher will be the loweirng of vapour pressure.
So barium nitrate will have highest lowering in vapour pressure

Order will be barium nitrate>Nacl>glucose

Thanks
All the very best.
22 Views

Is HC Verma is sufficient for physics in JEE ADVANCED . R.D sharma and M.L khanna for MATHMATICS in JEE ADVANCED.....

Avishek Dutta 6th Dec, 2019
HC Verma and ML Khanna are good books for JEE but arenit sufficient.
For physics
1.Buy NCERT for understanding the syllabus and studying the basics
2.Buy any one of this
i.Arihant ii.Cengage
Now I woukd prefer Cengage for JEE advanced as the book thoroughly follows jee advanced patterns.
And now study and solve them .
3.You can solve HC Verma or IRODOV if you want.
For Mathematics
1.Buy Cengages or Arihant books
Solve as much as you can from them
2.Tomato can be also a good book for solving.
Atlast solve the previous years JEE papers .
11 Views

Which book is most important for physics , chemistry and mathematics for JEE ADVANCED... for 2021 exam.. From now onwards

Saurabh Siddharth 6th Dec, 2019

Following is the list of few books for better preparation of JEE ADVANCE:

  • Physics- DC PANDEY, HC VERMA, CENGAGE
  • CHE- CENGAGE, NCERT (has much importance for inorganic and organic)
  • MATHS- CENGAGE, AARIHANT

You can prefer any book from above.

Suggestions

  • Do NCERT as well for jee advance. It would help you much.

Do HC Verma alongwith anyone to the other two but atleast complete anyone book. HC Verma would help you to clear the basics and you find it easy to solve other books after going through it.


34 Views

what is the cut off jee advance last 5 years

Halry Bhalodia 6th Dec, 2019

hello parag ,

cutoff for jee advance for last four years goes as :

  • Minimum Percentage of Marks in Each Subject  (A)
  • Minimum Percentage of Aggregate Marks  (B)

year  (category)      A                                   B

2019

CRL                            10.0                              25.0

OBC                           09.0                              22.5

SC                              05.0                              12.5

ST                               05.0                              12.5

2018

CRL                            10.0                              25.0

OBC                           09.0                              22.5

SC                              05.0                              12.5

ST                              05.0                              12.5

2017

CRL                            10.0                              35.0

OBC                           09.0                              31.5

SC                              05.0                              17.5

ST                              05.0                              17.5

2016

CRL                            10.0                              20.0

OBC                           09.0                              10.5

SC                              05.0                              10.5

ST                              05.0                              10.5

before this cutoff was based on subjects .


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