About SET 2013: SET is an entrance exam organized by the Symbiosis Institute of Technology to provide admission to the eligible candidates for various courses in engineering in the University.Symbiosis Institute of Technology announces B.Tech Admissions through SET 2013, Click here to apply online.
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Hello! The answer to this is that
the image will disappear
. We know that
1/f=(u2/u1 - 1)(1/R1 - 1/R2)
where u1= refractive index of medium of object
u2= refractive index of lens
and R1 and R2 are the radius of curvature of the two surfaces of lens.
We know that:
1/f= 1/v - 1/u and also
1/f= (Ureal - 1)(1/R1 - 1/R2)
where Ureal= refractive index in which the set up is kept.
Now, when we immerse the whole apparatus in water then Ureal changes and as you changes f also changes. Now, the value of u will be same but f changes so the value of v also changes but the SCREEN IS KEPT AT THE SAME DISTANCE AS BEFORE so the image will not coincide on the screen and
it will disappear.
Hope the answer helps.
As per the previous years, cutoff trends for admission into JNTU, Kakinada, the closing ranks for the domain of Electronics and Communications Engineering for respective categories are:
-BC-A: 3030 closing rank.
-BC-B: 1982 closing rank.
-BC-C: 2101 closing rank.
For more information related to cutoff trends about JNTU, Kakinada please go to the following link:
Hope this helps, Good Luck.
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