JEE Main Result 2019
Manashjyoti, 6 days ago, #JEE Main
Applications Open Now
Manav Rachna University B.Tech Admissions 2019
Apply
PDM University
Apply

JEE Main Result 2019 - National Testing Agency (NTA) has released the JEE Main 2019 Paper 2 result for April session on May 14 in online mode. Candidates are required to log in and enter their application number and date of birth or password to check the result of JEE Main 2019 Paper 2 exam and know their scores. The exam authorities has already released JEE Main 2019 result of Paper 1 for April session. The JEE Main result 2019 will show normalized scores for all three subjects as well as the total marks with rank. The official JEE Main result date of Paper 1 was April 30. The JEE Main 2019 result will also mention the qualifying status of the candidate for JEE Advanced. Candidates who qualify in JEE Main exam 2019 will be eligible to appear for JEE Advanced 2019. For candidates who have appeared in both January and April exam, the scores obtained in both sessions will be mentioned in the JEE Main 2019 result. JEE Main scores are used for admissions to the B.Tech courses at top institutes like NITs, IIITs, and GFTIs. To learn more about JEE Main result 2019 go through the rest of the article.
Latest: JEE Main 2019 Paper 2 result for April session announced
Latest: JEE Main 2019 final Answer Key available in PDF format.

JEE Main Paper 2 2019 result declared in online mode on May 14, 2019. Candidates can able to download their JEE Main Paper 2 result 2019 by logging in through their application number and password.

Latest: [Know admission chances for NIT's, and other B.Tech Colleges based on your JEE Main 2019 Rank] - JEE Main College Predictor

How to Check JEE Main April 2019 Result for Paper 1

JEE Main 2019 College Predictor

Know admission chances for NIT's, and other B.Tech Colleges based on your JEE Main 2019 Rank

Predict Now

JEE Main 2019 Paper I April exam was conducted in two shifts (forenoon and afternoon) on April 8, 9, 10 and 12. Paper 2 was conducted on April 7.

Applications Open Now
UPES - School of Engineering
B.Tech Admissions 2019 Open | 167+ Recruiters
Apply
Chandigarh University
Apply to M.E. in Chandigarh University | Highest Package 31.77 LPA
Apply

Till 2018, JEE Main was conducted by CBSE, but is now being conducted by the National Testing Agency in computer-based mode only. In another major change, the JEE Main 2019 will now be conducted twice a year – once in January and again in April.

Important Dates related to JEE Main Result 2019

Particulars for April ExamDates
Exam DatesPaper 2 - April 7, 2019
Paper 1 - April 8, 9, 10 and 12, 2019

Release of Answer Key and OMR Sheets

Available
JEE Main 2019 Result for Paper 1 declarationApril 29, 2019 (Announced)
JEE Main 2019 Result for Paper 2 declaration
May 14, 2019 (Announced)

Particulars for January Exam

JEE Main January exam

January 9,10,11 and 12 (Concluded)

Release of Provisional Answer Key

January 15, 2019

Release of FinalAnswer Key


January 23, 2019 (For Paper 1)
January 31, 2019 (For Paper 2)

Declaration of January Paper 1 Result (Announced)

January 19, 2019

Declaration of Paper 2 Result (Announced)January 31, 2019

How to check JEE Main 2019 Result?

  1. Go to the official website of JEE Main 2019 (jeemain.nic.in)
  2. Click on the JEE Main result 2019 link which will lead to the Candidate Login
  3. Candidates will have to provide their JEE Main application number and date of birth/password
  4. Click on Submit
  5. Upon successful log-in, the result of JEE Main 2019 would be displayed on screen in the form of scores.
  6. Download the result
  7. Candidates are requested to take a printout for future admission process.

Details included in JEE Main Result 2019

The JEE Main 2019 result will contain the following information:

  • Name of the candidate

  • Roll number

  • Date of birth

  • Name of the candidate’s parents

  • State code of eligibility

  • Category and Nationality

  • Subject-wise NTA scores

  • Total NTA scores obtained in first attempt and second attempt

  • Best of the two scores

  • Cutoff for JEE Advanced


Candidates who will appear in both the attempts- The score card for the candidates who will appear in both the attempts was declared on April 29 along with the rank list. The four NTA scores for each of the candidates in Paper-1 of JEE Main 2019 for the first attempt as well as for the second attempt were merged for compilation of result and preparation of overall Merit List. The best of the two NTA scores will be considered for further processing.

JEE Main 2019 Result (Final) looks like the image below



Image caption

JEE Main April 2019 Candidates who received 100 NTA Score in January and April Session

Candidate Name

State Code of Eligibility

Shubhan Srivastava

Delhi

Kevin Martin

Karnataka

Dhruv Arora

Madhya Pradesh

Jayesh Singla

Punjab

Battepati Karthikeya

Telangana

Nishant Abhangi

Rajasthan

Adelly Sai Kiran

Telangana

Vishwanth K

Telangana

Konda Renu

Andhra Pradesh

Abhay Pratap Singh Rathore

Madhya Pradesh

Sambit Behera

Rajasthan

Shubhankar Gambhir

Rajasthan

Ankit Kumar Mishra

Maharashtra

Himanshu Gaurav Singh

Uttar Pradesh

Prakhar Jagwani

Madhya Pradesh

Dravya Marwaha

Haryana

Naman Gupta

Uttar Pradesh

Gupta Kartikey Chandresh

Maharashtra

Yindukuri Jayanth Phani Sai

Telangana

Samiksha Das

Rajasthan

Bojja Chetan Reddy

Andhra Pradesh

Gudipaty Aniket

Jharkhand

Jitender Kumar Yadav

Haryana

Raj Aryan Agrawal

Maharashtra


For state wise toppers and more, read JEE Main 2019 Toppers

JEE Main 2019 Statistics (Both Attempts)

Number of common candidates registered in both January and April sessions

6,46,386

Number of appeared candidates registered in both January and April sessions

6,08,440

Number of candidate registered in January session

9,29,198

Number of candidate appeared in January session

8,74,469

Number of candidate registered in April session

9,35,755

Number of candidate appeared in April session

8,81,096

Total number of unique candidates registered in JEE Main

2019 (January and April)

12,37,892

Total number of unique candidates appeared in JEE Main

2019 (January and April)

11,47,125

JEE Main 2019 Paper 1 Toppers (January Exam) who scored 100 percentile:

S.No.

Application No.

Candidate Name

State Code of Eligibility

1

190310086378

DHRUV ARORA - Click here to read interview

MADHYA PRADESH

2

190310096437

RAJ ARYAN AGRAWAL

MAHARASHTRA

3

190310126508

ADELLY SAI KIRAN

TELANGANA

4

190310131614

BOJJA CHETAN REDDY - Click here to read the interview

ANDHRA PRADESH

5

190310139257

SAMBIT BEHERA Click here to read interview

RAJASTHAN

6

190310150035

NAMAN GUPTA

UTTAR PRADESH

7

190310166518

YINDUKURI JAYANTH PHANI SAI

TELANGANA

8

190310167837

VISHWANTH K

TELANGANA

9

190310204122

HIMANSHU GAURAV SINGH

UTTAR PRADESH

10

190310208678

KEVIN MARTIN

KARNATAKA

11

190310240908

SHUBHANKAR GAMBHIR

RAJASTHAN

12

190310244684

BATTEPATI KARTHIKEYA

TELANGANA

13

190310324762

ANKIT KUMAR MISRA

MAHARASHTRA

14

190310378068

JAYESH SINGLA

PUNJAB

15

190310597090

GUPTA KARTIKEY CHANDRESH

MAHARASHTRA


JEE Main 2019 Paper 2 Toppers who scored 100 Percentile

S.No.

Application Number

Name of Candidate

State Code of Eligibility

1.

190310031218

Gollapudi N Lakshman Narayana

Andhra Pradesh

2.

190310155658

Gudla Raghunandan Reddy

Andhra Pradesh


Check the video on JEE Main 2019 Result and Toppers below


JEE Main 2019 State wise Toppers with NTA Scores

S.No.

State Code of Eligibility

Candidate Name

NTA Score

1

ANDAMAN AND NICOBAR ISLAND

SHUBHANSHU PRASAD

98.7250736

2

ANDHRA PRADESH

BOJJA CHETAN REDDY

100.0000000

3

ARUNACHAL PRADESH

PRINCE KUMAR GUPTA

98.8802243

4

ASSAM

PRADIPTA PARAG BORA

99.9963677

5

BIHAR

ABHISHEK KUMAR

99.9771914

6

CHANDIGARH

DISHANK JINDAL

99.9972510

7

CHHATTISGARH

RISHABH BHATNAGAR

99.9727580

8

DADRA AND NAGAR HAVELI

VISHWAJEET DESHMUKH

98.8751498

9

DAMAN & DIU

ASHMIT SINGH

99.3978968

10

DELHI

NAVNEET JINDAL

99.9990830

11

FOREIGN/OCI/PIO/NEPAL/BHUTAN

ANANYA AMANCHERLA

99.8928714

12

GOA

JAIPRAKASH SURESH GURAV

99.9872898

13

GUJARAT

RAGHAV SOMANI

99.9907511

14

HARYANA

ASHUTOSH SINGLA

99.9981753

15

HIMACHAL PRADESH

SARTHAK GUPTA

99.8950807

16

JAMMU AND KASHMIR

AMAN YADAV

99.9789101

17

JHARKHAND

ANKIT KUMAR JAIN

99.9899608

18

KARNATAKA

KEVIN MARTIN

100.0000000

19

KERALA

VISHNU VINOD

99.9990801

20

LAKSHADWEEP

ABDUL JAVAD PA

88.3358227

21

MADHYA PRADESH

DHRUV ARORA

100.0000000

22

MAHARASHTRA

ANKIT KUMAR MISRA

100.0000000

23

MAHARASHTRA

GUPTA KARTIKEY CHANDRESH

100.0000000

24

MAHARASHTRA

RAJ ARYAN AGRAWAL

100.0000000

25

MANIPUR

LAISHRAM PRINCE SINGH

97.5009989

26

MEGHALAYA

GOURAV KUMAR

99.8872894

27

MIZORAM

AKASH JYOTI SAHOO

94.5211630

28

NAGALAND

KARTIKEYA CHANDRA

96.7983937

29

ODISHA

SIBASIS NAYAK

99.9844902

30

PUDUCHERRY

CHIRANTANDIP MAHANTA

99.7827873

31

PUNJAB

JAYESH SINGLA

100.0000000

32

RAJASTHAN

SHUBHANKAR GAMBHIR

100.0000000

33

RAJASTHAN

SAMBIT BEHERA

100.0000000

35

SIKKIM

RAHUL GUPTA

99.1418764

36

TAMIL NADU

GAURAV P

99.9935610

37

TELANGANA

ADELLY SAI KIRAN

100.0000000

38

TELANGANA

YINDUKURI JAYANTH PHANI SAI

100.0000000

39

TELANGANA

BATTEPATI KARTHIKEYA

100.0000000

40

TELANGANA

VISHWANTH K

100.0000000

41

TRIPURA

SHAYANDEEP BHAUMIK

99.7457412

42

UTTAR PRADESH

HIMANSHU GAURAV SINGH

100.0000000

43

UTTAR PRADESH

NAMAN GUPTA

100.0000000

44

UTTARAKHAND

PALLAV SEMWAL

99.9556053

45

WEST BENGAL

SHASWATA DUTTA

99.9972491

JEE Main 2019 Result: Percentile Scores and Rank Calculation

How is the JEE Main result 2019 calculated?

The normalized scores for JEE Main 2019 result will be calculated per session using the the following.

  • Raw Scores
  • Percentiles scores separately for each of the three subjects (Mathematics, Physics, Chemistry)
  • Percentile scores for the total marks.

Candidates may note that 4 Percentiles would be calculated for each in the session as follows

Let T1 (Total), M1 (Mathematics), P1 (Physics), C1 (Chemistry) be the raw scores of the candidate

Let T1P , M1P , P1P , C1P be the Percentile Scores of Total, Mathematics, Physics, Chemistry of that candidate.

Normalization formula used for result of JEE Main:


Total Percentile (T1P):


100 X

No. of candidates appeared from the session with raw score

EQUAL TO OR LESS than T1 score

Total No. of candidates appeared in the session


Mathematics Percentile (M1P):


100 X

No. of candidates appeared from the session with raw score

EQUAL TO OR LESS than M1 score in Mathematics

Total No. of candidates appeared in the session


Physics Percentile (P1P):


100 X

No. of candidates appeared from the session with raw score

EQUAL TO OR LESS than P1score in Physics

Total No. of candidates appeared in the session


Chemistry Percentile (C1P):


100 X

No. of candidates appeared from the session with raw score EQUAL TO OR LESS than C1score in Chemistry

Total No. of candidates appeared in the session


Declaration of the final result of JEE Main and All India Ranking

The process of compilation of the JEE Main result 2019 will be as follows

JEE Main Result compilation (First attempt)

NTA scores were calculated corresponding to the raw marks obtained by a candidate in each session as per the given formula. The calculated NTA scores for all the sessions were merged for declaration of result declared on January 19. The JEE Main result 2019 comprised of the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the first attempt held in January.

Compilation of JEE Main Result 2019 (Second attempt):

NTA will declare the scores corresponding to the raw marks obtained by a candidate in each session on April 30. The calculated NTA scores comprising the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt for all the sessions will be merged for the result declaration.

Compilation of Final JEE Main Result and Preparation of Merit List / Ranking:

The four NTA scores for each candidate for the first and second attempts will be merged for compilation of final result of JEE Main 2019 and preparation of overall Merit List / Ranking. The best of the two NTA scores will be considered for further for preparation of Merit List /Ranking as explained in the following example:

Example of JEE Main Ranking calculation


Roll No


First Attempt – NTA Score

Second Attempt-NTA Score

Final NTA Score for compilation of result

(best of the two in Total)



C20045511

Total

99.8620723

99.8740051

99.8740051

Mathematics

99.6249335

100.0000000

100.0000000

Physics

99.7338237

99.2102271

99.2102271

Chemistry

99.8572327

99.7203528

99.7203528



C20045512

Total



Did not Appear

99.8620723

99.8620723

Mathematics

99.6249335

99.6249335

Physics

99.7338237

99.7338237

Chemistry

99.8572327

99.8572327



C20045513

Total

99.8740051



Did not Appear

99.8740051

Mathematics

100.0000000

100.0000000

Physics

99.2102271

99.2102271

Chemistry

99.7203528

99.7203528



C20045514

Total

99.8740051

99.8620723

99.8740051

Mathematics

100.0000000

99.6249335

100.0000000

Physics

99.2102271

99.7338237

99.2102271

Chemistry

99.7203528

99.8572327

99.7203528


JEE Main Marks vs Percentile

With the new ranking system announced by NTA using the normalized scores of the candidates, the big question is how to calculate the JEE Main percentile for the marks obtained? The table below details the JEE Main marks vs percentile based on the trends of the past years. Candidates can estimate their JEE Main result 2019 using the table below.

Details of JEE Main Marks vs Percentile

JEE Main Marks

Percentile

360 to 310

100 - 99.98724751

309 to 299

99.985572 - 99.9740296

298 to 288

99.97589128 - 99.96258028

287 to 278

99.96146328 - 99.94424276

277 to 268

99.94098483 - 99.91929629

267 to 258

99.91836545 - 99.89081262

257 to 248

99.88643768 - 99.84845946

247 to 238

99.84510844 - 99.79959043

237 to 228

99.79679791 - 99.73294238

227 to 218

99.73005678 - 99.65475193

217 to 208

99.64888765 - 99.55273201

207 to 198

99.54919482 - 99.43609792

197 to 188

99.4200875 - 99.28958392

187 to 178

99.26473052 - 99.07781811

177 to 168

99.06329703 - 98.85683701

167 to 158

98.82509541 - 98.55710695

157 to 148

98.53104347 - 98.20040957

147 to 138

98.14939961 - 97.75686494

137 to 128

97.69477799 - 97.17648701

127 to 118

97.13841571 - 96.41990133

117 to 108

96.35511496 - 95.49744019

107 to 98

95.42678954 - 94.40128456

97 to 88

94.19473145 - 92.74709113

87 to 78

92.61891464 - 90.64227869

77 to 68

90.42902355 - 87.34180397

67 to 58

87.34180397 - 82.68016383

57 to 48

81.92571907 - 75.39020758

47 to 38

74.13450619 - 64.11300382

37 to 28

62.88839244 - 49.28762915

27 to 18

49.01228707 - 33.08815042

17 to 1

31.32570046 - 9.077538863


How to calculate JEE Main 2019 result (or rank) using answer keys?

The exam conducting body will release the JEE Main 2019 April attempt answer key and OMR sheets after the exam is conducted. Using these items, the candidates will be able to calculate their probable scores and in turn assess their chances of getting admission to an institute or course of their choice. When calculating probable scores, the candidates must strictly follow the marking scheme of the exam as outlined in JEE Main 2019 exam pattern.

Marking Scheme of JEE Main 2019

  • For every correct answer, the candidate will be awarded 4 marks

  • In case of incorrect attempt, 1 mark will be deducted

Using the OMR sheets, the candidate will be able to calculate the total number of correct and incorrect attempts. Next calculate the total positive and negative marks. The total score can be found by deducting the total negative marks from the total positive marks.

Total positive marks = (Total correct attempts) x 4

Total negative marks = (Total incorrect attempts) x 1

Total JEE Main Score = Total positive marks – Total negative marks

How is inter-se merit determined?

In case of a tie when two or more candidates obtain equal Total NTA Score in JEE Main 2019, inter-se merit of such candidates shall be determined in following order:

  • NTA score of raw mark in Mathematics
  • NTA score of raw mark in Physics
  • NTA score of raw mark in Chemistry
  • Candidates older in age
  • If the resolution is not possible after this criterion, candidates will be given the same rank

JEE Main 2019 Cutoff

Important information included on the result is the qualifying cutoff of JEE Main 2019. Only those candidates who meet or score above the JEE Main 2019 qualifying cutoff will be eligible to appear in JEE Advanced 2019, or else they will be disqualified. Please note that the cutoff of JEE Main is prepared based on factors like number of applicants, availability of seats, and also past trends.
The qualifying JEE Main cutoff 2019 is available, so candidates may refer the cutoffs of previous years’ to get an idea how much they might need to score.
JEE Main 2019 Cutoff Score

Category

Cutoff Score

Common Merit List

89.754849

General (EWS)

78.2174869

OBC

74.3166557

SC

54.0128155

ST

44.3345172

PWD

0.11371730

JEE Main 2018 Qualifying Cutoff

Category

Qualified

Max Marks

Min Marks

Common Rank List

111275

350

74

OBC-NCL

65313

73

45

SC

34425

73

29

ST

17256

73

24

PwD

2755

73

-35

Total

231024





As the table above shows, last year a total of 231024 candidates qualified for JEE Advanced. Candidates must note that the figure is flexible, as in 2017 only 224000 had qualified in the exam.

JEE Main 2017 Qualifying Cutoff

S.No.

Category

Cutoff

1

General

81

2

OBC-NCL

49

3

SC

32

4

ST

27

5

PWD

1

JEE Main Rank List 2019

NTA will prepare the rank list of JEE Main 2019 based on the four NTA scores.The scores for the first attempt as well as for the second attempt will be merged for compilation of result and preparation of overall Merit List / Rank list.Best of the two NTA scores will be considered for the candidates who will give both the attempts of January and of April.

JEE Main Marks Vs Rank

Joint Seat Allocation Authority (JoSAA), the sole body responsible for joint seat allocation, releases the seat allotment result in the form of ranks only. Now many candidates who plan to appear in JEE Main 2019 might have a specific score in their mind that they are targeting. But how do these candidates know the corresponding rank for that score. One way of finding out the rank for a particular score is get in tough with candidates who have themselves appeared in the exam. But it is a tedious exercise, and cannot be adopted to find out the corresponding ranks for a whole range of scores. So, in a bid to make the candidates’ job a bit easier, we bring you JEE Main ranks vs marks. While the comparison is not full proof, they are closer to the real thing.

JEE Main Marks Vs Rank

Marks

Rank Range

301 to 360

1 - 9

281 to 300

10 - 83

261 to 280

84 - 244

241 to 260

245 - 706

221 to 240

707 - 1755

201 to 220

1756 - 4163

181 to 200

4164 - 8997

161 to 180

8998 - 18371

141 to 160

18372 - 35928

121 to 140

35929 - 67649

101 to 120

67651 - 125722

81 to 100

125723 - 237034

61 to 80

237035 - 463443

41 to 60

463444 - 844544

21 to 40

844546 - 1093113

1 to 20

1093115 - 1121966

What is the difference between Percentage and Percentile score?

Many of us have made the mistake of assuming percentage and percentile to be the same thing, when in fact they are different. For example, one of the eligibility criteria for admission at the NITs, IIITs, and GFTIs is candidates must be placed inside the top 20 percentile of respective boards (10+2 exam) to be eligible for admission. Now unless the candidates knows what percentile means, there are chances mistakes may happen. That is why we have thought it prudent to explain the difference between the two terms.

Difference between percentage and percentile

Percentage

Percentile

Percentage = marks obtained / total marks x 100


Percentile = 100 x Number of candidates in the group with aggregate marks less than that obtained by the candidate/ Total number of candidates in the group

For the purpose of admission, category-wise top 20 percentiles are accepted. This means the top 20 percentile list will be different for general, OBC, ST and PwD categories.

Take for example, if the total number of candidates who have registered in a particular board is 14111 and total number of candidates who appeared in the entrance exam is 13991, then, then the percentile will be calculated as:

Percentile of a student who has scored 50% marks in the Board where 2250 candidates have scored below him

Percentile score for 50% marks in the Board will be calculated as 2250 x 100/ 13991 = 16.081

Subject-combination for calculating top 20 percentile

The subject combination for calculating top 20 percentile will vary depending on whether the candidate wants to get admission in B.Tech courses or B.Arch courses.

A. Subject-combination for B.Tech courses

For calculating top 20 percentile for candidates belonging to this category, the following five subject combination will be accepted.

  • Language

  • Physics

  • Mathematics

  • Any one of (Chemistry, Biology, Biotechnology, Technical Vocational Subject

  • Any other subject

Note: In a candidate has studies 6 subjects in the qualifying exam, in such cases the better of the fifth or sixth will be considered.

B. Subject combination for B.Arch/B.Plan

The following subject combination will be considered for calculating the top 20 percentile for admission to B.Arch/B.Planning courses:

  • Mathematics

  • Any other four subjects.

JEE Main 2018 Statistics

Description

No. of Boys

No. of Girls

Transgender

Total

Total Candidates Registered for Paper 1

815005

320077

2

1135084

Candidates Registered for Offline Exam

639205

258559

2

897766

Candidates Registered for Online Exam

175800

61518

-

237318

Candidates Appeared for Offline Exam

615242

242321

1

857564

Candidates Appeared for Online Exam

161716

55039

-

216755

Candidates Qualified for Appearing in JEE Advanced

180331

50693

-

231024

Previous Year's JEE Main Seat Matrix

S.No

Institutes

Total Number of Seats

1

Indian Institute of Information Technology (IIITs)

4023

2

National Institute of Technology (NITs)

17967

3

Government Funded Technical Institutes

4683

FAQs on JEE Main 2019 Result

Q. How to know if qualified for JEE Advanced 2019 exam?

A. Candidates who got more than or equal to cut off (category wise) released by NTA will be qualified for the JEE Advanced exam 2019. Only the top 2,45,000 JEE Main 2019 qualified candidates will be eligible for JEE Advanced examination. You can check your cut off in your JEE Main 2019 score card.

Q. How to check eligibility for JEE Advanced 2019?

A. The followings are the eligibility to appear for JEE Advanced examination,

  • Age limit – The Supreme Court of India has released an order declaring that candidates who are above the age of 25 years can apply for JEE Advanced 2019.
  • Qualifying examination – The candidates should have appeared and qualified 12th standard (or equivalent) examination in 2018 or 2019.
  • Number of attempts – JEE Advanced can be attempted by the candidates two times in two consecutive years.
  • JEE Main – All of the candidates have to qualify JEE Main exam and satisfy the specified cutoff for admissions into IITs through JEE Advanced exam.
  • IIT Admissions – Should not have been admitted in an IIT irrespective of whether or not he/she continued in the programme or accepted an IIT seat by reporting at a reporting centre in the past. Those candidates whose admission at IITs was cancelled after joining will also not be considered eligible for JEE Advanced.

Q. How many students appeared in JEE Mains 2019?

A. There are 608440 candidates were appeared in the January session and similarly, there are totally 881096 candidates participated in the April session. 77% of students appeared in both the sessions of JEE Main 2019 examination i.e., 1147125 candidates.

Q. What will my JEE Main result in April contain?

A. The JEE Main result 2019 to be declared in April will give the percentile scores and the ranks obtained by the students. The ranks will be used as the basis for admissions.

Q. How will I know my best score? Will the April and January scores be given separately?

A. To allow candidates a clear idea, both the January and April scores will be mentioned and the rank will also be mentioned.

Q. How will the ranking be calculated for JEE Main 2019 considering both the attempts?

A. JEE Main 2019 ranks will be calculated on the basis of the final percentile that will be mentioned for each candidate. The best of the two scores will be used for candidates who have appeared in both the sessions while the score of the session appeared will be used for all others.

Q. Since percentile can be same in a session for two or more candidates, how will the ranks be awarded?

A. Well, the ranking will be as per the inter-se-merit guidelines which are discussed in detail in the article above. The ranks will be awarded as per the same.

Q. How can I know for which percentile I will get a seat?

A. This unfortunately is something that cannot be predicted just like that. Its better to use a rank predictor tool that uses past trends keeping your category in mind and then gives all those options.

Q. Will the JEE Advanced qualifying status be announced with the JEE Main 2019 result?

A. Yes, the cutoff marks as well as JEE Advanced qualifying status will be announced by NTA with the JEE Main result 2019. It must be noted that this is the cutoff to appear for JEE Advanced and not for admissions through JEE Main.

Q. Should I drop one year if I dont get the requisite percentile for admissions?

A. This is not advisable as statistics show very few candidates succeeding in their second attempt. It is more prudent to take admissions in colleges /universities other than NITs, IIITs or GFTIs. That way you won't waste one whole year. However, if you are strong minded about the reattempt and willing to work very hard, you may also choose to do so.

Q. Can I ask for revaluation of the result of JEE Main 2019?

A. No, you cannot ask for revaluation. This is a computer based test hence chances of malpractices are less and NTA does not entertain revaluation.

Q. I think I should have got more marks when I check the answer key but my result shows a lower percentile?/ Can I get clarity on this?

A. Actually, NTA will release your marks and percentile. To know the calculation behind it, you will require statistics on how many students attempted the test along with you which NTA does not release. So chances of clatiry on this is practically nil.

Applications Open Now

UPES - School of Engineering
UPES - School of Engineering
Apply
IIMT-College of Engineering
IIMT-College of Engineering
Apply
Ganga Group Of Institutions-B.Tech Admissions
Ganga Group Of Institutions-B...
Apply
Bennett University B.Tech Admissions
Bennett University B.Tech Adm...
Apply
PDM University
PDM University
Apply
Chandigarh University
Chandigarh University
Apply
Manav Rachna University B.Tech Admissions 2019
Manav Rachna University B.Tec...
Apply
View All Application Forms

More like JEE Main

Questions related to JEE Main

I have got 90 percentile in jee mains paper 2 suggest me some best colleges to join

1 Hour ago

Hi aspirant Congratulations on securing such a nice percentile in Jee mains 2019, you can get admission with this percentile in nit using your cat...

I got Jee Mains 92.7230714 persentail how many marks

2 Hours ago

Hello Bhumi, based on last year marks trend your marks would be somewhere around 90. But don't be fully dependent on this prediction because it is ...

I am confused about my ISC improvement exams, if I try for4 subjects out of 6, then how will my percentage be calculated for JEE main

1 Hour ago

Hello Jitendra,If you try for 4 subjects out of 6 in ISC improvement exam ,then your marks which will be considered are the marks in these 4 examin...

I got 82.38 percentile and my category is EWS and my general rank is around 2,00,000 and category is around 20,000 so which best college ?

2 Hours ago

Hello!This is very low rank. At this rank you can,t get NITs or IIITs you may get a seat in GFTIs college so go for it.You may check last year cuto...

I GOT JEE RANK 31152 IN OPRN CAT. IS THERE ANY CHANCE TO GET AN SEAT IN DAIICT?

2 Hours ago

Hello Shivashish, You have not specified your home state because it is very important in determining your course and college. Based on the last yea...

Top

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

Careers360 App
150M+ Students
24,000+ Colleges
500+ Exams
1500+ E-books