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JEE Main Result 2020 - NTA will declare the result of JEE Main 2020 in online mode on January 31 for January session. The JEE Main 2020 result for April attempt will be released on April 30. The JEE Main result will be declared in the form of score card containing four NTA scores, one each for Physics, Chemistry and Mathematics and one combined score. The JEE Main 2020 result will also mention the All India Rank and Category Rank of candidates. The final result of JEE Main 2020 is formulated after the April attempt on the basis of candidates performance in January and/ or April attempt. JEE Main result 2020 for candidates who appear in both January and April attempt will be formulated using the best of two scores. Students who qualify JEE Main 2020 will become eligible to appear in JEE Advanced 2020. The JEE Main score is used for admission in NITs, IIITs, GFTIs and many other institutes. Candidates can find below more details regarding the JEE Main result 2020 and the various process involved in admission.Latest: Students of J&K can now fill the online JEE Main application form 2020 till November 8.
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January Attempt Dates
April Attempt Dates
JEE Main 2020 Exam
January 6 to 11, 2020
April 3 to 9, 2020
Release of Provisional Answer Key
January second week
April second week
Release of Final Answer Key
January third week
April third week
Declaration of Result
January 31, 2020
April 30, 2020
Registration for JEE Advanced 2020
May first week, 2020
JEE Advanced 2020
May Second week, 2020
JEE Advanced 2020 Result
May last week, 2020
Registration for JoSAA 2020 Counselling
June 15, 2020
NTA will declare the result of JEE Main 2020 in online mode separately for both the attempts. The direct link for checking JEE Main result 2020 will be provided below once it is declared. The January attempt result will be declared on January 31 and the April attempt result will be declared on April 30, 2020. Students can check the result by login either by using their Application Number and Password or with Application Number and Date of Birth. Following is the step by step guide to check JEE Main Result 2020
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Open the JEE Main 2020 Portal : jeemain.nic.in
Click on the result link
Login using JEE Main 2020 Application Number and Password/ Date of Birth
Result will be displayed on screen
Download the result and take a print of it
Keep the result copy safe till the complete admission process
Students will find the following details in their result of JEE Main 2020
Name of the candidate
Date of birth
Name of the candidate’s parents
State code of eligibility
Category and Nationality
Subject-wise NTA scores
Total NTA scores obtained in first attempt and second attempt
Best of the two scores
All India Rank of Candidate
Category Rank of Candidate (If applicable)
Cutoff for JEE Advanced
JEE Main 2019 State-wise Toppers with NTA score
State Code of Eligibility
ANDAMAN AND NICOBAR ISLAND
BOJJA CHETAN REDDY
PRINCE KUMAR GUPTA
PRADIPTA PARAG BORA
DADRA AND NAGAR HAVELI
DAMAN & DIU
JAIPRAKASH SURESH GURAV
JAMMU AND KASHMIR
ANKIT KUMAR JAIN
ABDUL JAVAD PA
ANKIT KUMAR MISRA
GUPTA KARTIKEY CHANDRESH
RAJ ARYAN AGRAWAL
LAISHRAM PRINCE SINGH
AKASH JYOTI SAHOO
ADELLY SAI KIRAN
YINDUKURI JAYANTH PHANI SAI
HIMANSHU GAURAV SINGH
Candidates who scored 100 Percentile in JEE Main 2019
Adelly Sai Kiran
Abhay Pratap Singh Rathore
Ankit Kumar Mishra
Himanshu Gaurav Singh
Gupta Kartikey Chandresh
Yindukuri Jayanth Phani Sai
Bojja Chetan Reddy
Jitender Kumar Yadav
Raj Aryan Agrawal
JEE Main 2019 Paper 2 Toppers who scored 100 Percentile
Name of Student
Gollapudi N Lakshman Narayana
Gudla Raghunandan Reddy
Marking scheme of JEE Main 2020
NTA follows the predetermined marking scheme for calculating the marks obtained in each part of the question paper. The marking scheme is discussed below
For every correct answer
4 marks is awarded
For wrong answers
1 mark is deducted
For unanswered question
No mark is awarded or deducted
JEE Main result is calculated in the form of percentile NTA score each for Physics, Chemistry and Mathematics and one combined score. NTA scores are obtained by normalization using the raw score obtained by the candidates. The following formula is used for obtaining the NTA score
Total Percentile (T1P):
No. of candidates appeared from the session with raw score EQUAL TO OR LESS than T1 score
Total No. of candidates appeared in the session
Mathematics Percentile (M1P)
No. of candidates appeared from the session with raw score EQUAL TO OR LESS than M1 score in Mathematics
Physics Percentile (P1P)
No. of candidates appeared from the session with raw score EQUAL TO OR LESS than P1 score in Physics
Chemistry Percentile (C1P):
No. of candidates appeared from the session with raw score EQUAL TO OR LESS than C1 score in Chemistry
Declaration of the final result of JEE Main 2020 and All India RanksJEE Main 2020 will be conducted in two attempts in January and April. Since the exam will be held on multiple shifts each day across the two sessions, the calculation of score to a single percentile score is done through a normalization process. The normalization is done to reach a disambiguated score of candidates despite the variations in difficulty level of question papers held on multiple shifts and sessions. NTA adopts an established formula for the calculation of percentile score.
Compilation and display of Paper 1 Result for First January session:JEE Main 2020 Paper-1 first attempt will be conducted in multi-shifts, NTA scores will be calculated corresponding to the raw marks obtained by a candidate. This shall comprise of the four NTA scores for each of the three subjects (Mathematics, Physics, Chemistry) and the total in Paper-1 of JEE Main 2020 for the first attempt.
Compilation and display of Paper 1 Result after April session:Similarly, JEE Main 2020 Paper-1 second attempt will be conducted in multi-shifts, NTA scores will be calculated corresponding to the raw marks obtained by a candidate. The calculated NTA scores for the Raw Marks for all the shifts/sessions will be merged for further processing. The four NTA scores for each of the candidates in Paper-1 of JEE Main 2020 for the first attempt as well as for the second attempt will be merged for compilation of results and preparation of overall Merit List / Ranking. Those appeared in both the attempts; their best of the two NTA scores (total) will be considered for further processing.
Tie-BreakingIn case of a tie when two or more candidates obtain equal Total NTA Score in JEE Main 2020, inter-se merit of such candidates shall be determined in the following order:
If the resolution is not possible after this criterion, candidates will be given the same rank.The NTA scores of both the attempts and rank of Paper 1 of JEE Main 2020 for all candidates who appeared in first attempt as well as in second will be declared by April, 2020. This shall comprise the four NTA scores obtained by the candidate in first attempt and four NTA scores obtained in second attempt along with the status of those who qualify for appearing in JEE Advanced 2020 provided and subject to other conditions of eligibility being met. The rank shall comprise All India rank and All India category rank
Compilation and display of Paper 2 Result for January sessionJEE Main 2020 Paper-2 may be conducted in single-shift only, the raw marks obtained by all the candidates who appeared in first attempt will be declared by January, 2020. This shall comprise the actual marks obtained in Paper-2 of JEE Main 2020 for the first attempt.
Compilation and display of Paper 2 Result after April sessionJEE Main 2020 Paper-2 second attempt also may be conducted in single-shift, the raw marks obtained by all the candidates who appeared in the second shift as well as for the first attempt will be merged for compilation of results and preparation of overall Merit List / Ranking. Those appeared in both the attempts; their best of the two raw marks will be considered for further processing.
In case of a tie when two or more candidates obtain equal Total Marks in JEE Main 2020, inter-se merit of such candidates shall be determined in the following order:
If the resolution is not possible after this criterion, candidates will be given the same rank.The Total raw marks of both the attempts and rank of Paper-2 of JEE Main 2020 for all candidates who appeared in first attempt as well as in second will be declared by April, 2020. This shall comprise the total raw marks obtained by the candidate in first attempt as well as in second attempt along with All India rank and All India category rank.
Difference between percentage and percentile scoreStudents must note that percentage and percentile are two different entities. Percentage is the absolute number while percentage is relative. If a student obtained 90 marks out of 100, his/her percentage will be 90 but percentile would be different. Percentile is calculated in relation to the total number of candidates appeared. The formula for calculating the percentage and percentile is given below
Marks obtained / Total marks (x) 100
100 (x) Number of candidates in the group with aggregate marks less than that obtained by the candidate / Total number of candidates in the group
NTA will declare the JEE Main cutoff 2020 along with the declaration of result. JEE Main cutoff is the minimum marks a candidate need to secure in order to qualify the exam. Students who score marks more than or equal to JEE Main cutoff becomes eligible to appear for JEE Advanced and also for taking admission in NITs, IIITs, GFTIs and other institutes which take admission through the score. JEE Main cutoff is different for various categories and varies year over year. Students can find below JEE Main Cutoff for previous year.
JEE Main 2019 Cutoff
Common Merit List
JEE Main Cutoff for previous years
NTA will release the JEE Main 2020 rank list along with the declaration of result. JEE Main rank list mentions the ranks obtained by students. NTA will release two types of rank, All India Rank and Category Rank. JEE Main 2020 Rank list will be prepared on the basis of candidates percentile score in the exam.
Students who qualify JEE Main are provided percentile NTA score and its corresponding All India Rank and Category Rank. Joint Seat Allocation Authority (JoSAA) uses the All India Rank of Candidates for the allotment of seats in all the participating institutes. Students can find the reference JEE Main Mark vs Rank criteria in order to get an idea about their rank as per their score
JEE Main Scores
JEE Main Ranks (CRL)
336 - 360
1 - 20
310 to 335
21 - 225
251 to 300
226 - 1492
201 to 250
1493 - 5752
151 to 200
5753 - 18377
101 to 150
18378 - 57131
51 to 100
57132 - 240541
1 to 50
240542 - 984170
-40 to 0
984171 - 1074221
JEE Main Marks vs PercentileThe result of JEE Main 2020 will be released in the form of NTA score, which is a percentile score obtained by normalization process. Normalization is done on the basis of candidates raw score obtained in each subject. Normalization is done to eliminate any parity in difficulty level of exam held across multiple session and shifts. The JEE Main result enlists percentile NTA score each for Physics, Chemistry and Mathematics and one combined score. Students can find for reference the JEE Main marks vs Percentile scores
JEE Main Marks
360 to 310
100 - 99.98724751
309 to 299
99.985572 - 99.9740296
298 to 288
99.97589128 - 99.96258028
287 to 278
99.96146328 - 99.94424276
277 to 268
99.94098483 - 99.91929629
267 to 258
99.91836545 - 99.89081262
257 to 248
99.88643768 - 99.84845946
247 to 238
99.84510844 - 99.79959043
237 to 228
99.79679791 - 99.73294238
227 to 218
99.73005678 - 99.65475193
217 to 208
99.64888765 - 99.55273201
207 to 198
99.54919482 - 99.43609792
197 to 188
99.4200875 - 99.28958392
187 to 178
99.26473052 - 99.07781811
177 to 168
99.06329703 - 98.85683701
167 to 158
98.82509541 - 98.55710695
157 to 148
98.53104347 - 98.20040957
147 to 138
98.14939961 - 97.75686494
137 to 128
97.69477799 - 97.17648701
127 to 118
97.13841571 - 96.41990133
117 to 108
96.35511496 - 95.49744019
107 to 98
95.42678954 - 94.40128456
97 to 88
94.19473145 - 92.74709113
87 to 78
92.61891464 - 90.64227869
77 to 68
90.42902355 - 87.34180397
67 to 58
87.34180397 - 82.68016383
57 to 48
81.92571907 - 75.39020758
47 to 38
74.13450619 - 64.11300382
37 to 28
62.88839244 - 49.28762915
27 to 18
49.01228707 - 33.08815042
17 to 1
31.32570046 - 9.077538863
Students can find here the seat matrix of JEE Main
All the participating institutes of JEE Main has reserved certain number of seats for candidates belonging to reserved categories. Admission to candidates belonging to reserved categories are done considering the reservation criteria mandated by the Government. Students can find below the percentage of seats reserved in the institutes.
Person with Disabilities
Economically Weaker Section
Students who will qualify JEE Main 2020 with the minimum cutoff mark as decided by the official authority becomes eligible to appear in JEE Advanced. Students can find below the previous year cutoff trends for appearing in JEE Advanced.
2019 (NTA Score)
Candidates who score more than or equal to cut off (category wise) released by NTA will be qualified for the JEE Advanced exam 2020. Only the top 2,45,000 JEE Main 2020 qualified candidates will be eligible for JEE Advanced examination. You can check your cut off in your JEE Main 2020 score card.
The followings are the eligibility to appear for JEE Advanced examination,
Age limit – The Supreme Court of India has released an order declaring that candidates who are above the age of 25 years can apply for JEE Advanced 2020.
Qualifying examination – The candidates should have appeared and qualified 12th standard (or equivalent) examination in 2019 or 2020.
Number of attempts – JEE Advanced can be attempted by the candidates two times in two consecutive years.
JEE Main – All of the candidates have to qualify JEE Main exam and satisfy the specified cutoff for admissions into IITs through JEE Advanced exam.
IIT Admissions – Should not have been admitted in an IIT irrespective of whether or not he/she continued in the programme or accepted an IIT seat by reporting at a reporting centre in the past. Those candidates whose admission at IITs was cancelled after joining will also not be considered eligible for JEE Advanced.
There are 608440 candidates were appeared in the January session and similarly, there are totally 881096 candidates participated in the April session. 77% of students appeared in both the sessions of JEE Main 2019 examination i.e., 11,47,125 candidates.
The JEE Main result 2020 to be declared in April will give the percentile scores and the ranks obtained by the students. The ranks will be used as the basis for admissions.
To allow candidates a clear idea, both the January and April scores will be mentioned and the rank will also be mentioned.
JEE Main 2020 ranks will be calculated on the basis of the final percentile that will be mentioned for each candidate. The best of the two scores will be used for candidates who have appeared in both the sessions while the score of the session appeared will be used for all others.
Well, the ranking will be as per the inter-se-merit guidelines which are discussed in detail in the article above. The ranks will be awarded as per the same.
This, unfortunately, is something that cannot be predicted just like that. Its better to use a rank predictor tool that uses past trends keeping your category in mind and then gives all those options.
Yes, the cutoff marks, as well as JEE Advanced qualifying status, will be announced by NTA with the JEE Main result 2020. It must be noted that this is the cutoff to appear for JEE Advanced and not for admission through JEE Main.
This is not advisable as statistics show very few candidates succeeding in their second attempt. It is more prudent to take admissions in colleges /universities other than NITs, IIITs or GFTIs. That way you won't waste one whole year. However, if you are strong-minded about the reattempt and willing to work very hard, you may also choose to do so.
No, you cannot ask for revaluation. This is a computer-based test hence chances of malpractices are less and NTA does not entertain revaluation.
Actually, NTA will release your marks and percentile. To know the calculation behind it, you will require statistics on how many students attempted the test along with you which NTA does not release. So chances of clarity on this is practically nil.
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There is no age limit for JEE Mains. To appear for JEE Mains 2020, you should be appearing either in January or April sessions of JEE Mains. For Candidates appearing for JEE 2020, Candidates should have passed their 12th either in 2018 or 2019. Going by that you are eligible for JEE Mains 2020. If the rules remain the same for JEE 2021, you should have completed your 12th either in 2020 or 2019. So with you passing your 12th in 2019, you are eligible for appearing Mains on both 2020 and 2021. For more information, please visit our page at:
Hello dear aspirant.
I think you will be well aware of the fact that from this year onwards there are certain changes in number of questions for JEE mains as well as their types and aggregate marks.
It is a little tough to predict 95 percentile but yes anything above 180 will be above 95 percentile most probably.
Moreover it may vary depending upon the difficulty level of exam paper.
Hope you get it.
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