Your browser does not support iframes.
JEE Main Result 2019 - National Testing Agency (NTA) has released the JEE Main 2019 Paper 2 result for April session on May 14 in online mode. Candidates are required to log in and enter their application number and date of birth or password to check the result of JEE Main 2019 Paper 2 exam and know their scores. The exam authorities has already released JEE Main 2019 result of Paper 1 for April session. The JEE Main result 2019 will show normalized scores for all three subjects as well as the total marks with rank. The official JEE Main result date of Paper 1 was April 30. The JEE Main 2019 result will also mention the qualifying status of the candidate for JEE Advanced. Candidates who qualify in JEE Main exam 2019 will be eligible to appear for JEE Advanced 2019. For candidates who have appeared in both January and April exam, the scores obtained in both sessions will be mentioned in the JEE Main 2019 result. JEE Main scores are used for admissions to the B.Tech courses at top institutes like NITs, IIITs, and GFTIs. To learn more about JEE Main result 2019 go through the rest of the article.Latest: The seventh round seat allotment of JoSAA 2019 declaredLatest: JEE Main 2019 Paper 2 result for the April session announcedJEE Main Paper 2 2019 result declared in online mode on May 14, 2019. Candidates can able to download their JEE Main Paper 2 result 2019 by logging in through their application number and password.
Latest: [Head Start your preparation for engineering exams with JEE Main Knockout Course], Click Here
How to Check JEE Main April 2019 Result for Paper 1
JEE Main 2019 Paper I April exam was conducted in two shifts (forenoon and afternoon) on April 8, 9, 10 and 12. Paper 2 was conducted on April 7.
Till 2018, JEE Main was conducted by CBSE, but is now being conducted by the National Testing Agency in computer-based mode only. In another major change, the JEE Main 2019 will now be conducted twice a year – once in January and again in April.
Head Start your preparation for engineering exams with JEE Main Knockout Course
Release of Answer Key and OMR Sheets
Particulars for January Exam
JEE Main January exam
January 9,10,11 and 12 (Concluded)
Release of Provisional Answer Key
January 15, 2019
Release of FinalAnswer Key
Declaration of January Paper 1 Result (Announced)
January 19, 2019
The JEE Main 2019 result will contain the following information:
Name of the candidate
Date of birth
Name of the candidate’s parents
State code of eligibility
Category and Nationality
Subject-wise NTA scores
Total NTA scores obtained in first attempt and second attempt
Best of the two scores
Cutoff for JEE Advanced
Candidates who will appear in both the attempts- The score card for the candidates who will appear in both the attempts was declared on April 29 along with the rank list. The four NTA scores for each of the candidates in Paper-1 of JEE Main 2019 for the first attempt as well as for the second attempt were merged for compilation of result and preparation of overall Merit List. The best of the two NTA scores will be considered for further processing.
JEE Main 2019 Result (Final) looks like the image below
JEE Main April 2019 Candidates who received 100 NTA Score in January and April Session
State Code of Eligibility
Adelly Sai Kiran
Abhay Pratap Singh Rathore
Ankit Kumar Mishra
Himanshu Gaurav Singh
Gupta Kartikey Chandresh
Yindukuri Jayanth Phani Sai
Bojja Chetan Reddy
Jitender Kumar Yadav
Raj Aryan Agrawal
For state wise toppers and more, read JEE Main 2019 Toppers
JEE Main 2019 Statistics (Both Attempts)
Number of common candidates registered in both January and April sessions
Number of appeared candidates registered in both January and April sessions
Number of candidate registered in January session
Number of candidate appeared in January session
Number of candidate registered in April session
Number of candidate appeared in April session
Total number of unique candidates registered in JEE Main
2019 (January and April)
Total number of unique candidates appeared in JEE Main
JEE Main 2019 Paper 1 Toppers (January Exam) who scored 100 percentile:
DHRUV ARORA - Click here to read interview
RAJ ARYAN AGRAWAL
ADELLY SAI KIRAN
BOJJA CHETAN REDDY - Click here to read the interview
SAMBIT BEHERA Click here to read interview
YINDUKURI JAYANTH PHANI SAI
HIMANSHU GAURAV SINGH
ANKIT KUMAR MISRA
GUPTA KARTIKEY CHANDRESH
JEE Main 2019 Paper 2 Toppers who scored 100 Percentile
Name of Candidate
Gollapudi N Lakshman Narayana
Gudla Raghunandan Reddy
Check the video on JEE Main 2019 Result and Toppers below
JEE Main 2019 State wise Toppers with NTA Scores
ANDAMAN AND NICOBAR ISLAND
BOJJA CHETAN REDDY
PRINCE KUMAR GUPTA
PRADIPTA PARAG BORA
DADRA AND NAGAR HAVELI
DAMAN & DIU
JAIPRAKASH SURESH GURAV
JAMMU AND KASHMIR
ANKIT KUMAR JAIN
ABDUL JAVAD PA
LAISHRAM PRINCE SINGH
AKASH JYOTI SAHOO
The normalized scores for JEE Main 2019 result will be calculated per session using the the following.
Candidates may note that 4 Percentiles would be calculated for each in the session as follows
Let T1 (Total), M1 (Mathematics), P1 (Physics), C1 (Chemistry) be the raw scores of the candidate
Let T1P , M1P , P1P , C1P be the Percentile Scores of Total, Mathematics, Physics, Chemistry of that candidate.
Normalization formula used for result of JEE Main:
Total Percentile (T1P):
No. of candidates appeared from the session with raw score
EQUAL TO OR LESS than T1 score
Total No. of candidates appeared in the session
Mathematics Percentile (M1P):
EQUAL TO OR LESS than M1 score in Mathematics
Physics Percentile (P1P):
EQUAL TO OR LESS than P1score in Physics
Chemistry Percentile (C1P):
No. of candidates appeared from the session with raw score EQUAL TO OR LESS than C1score in Chemistry
Declaration of the final result of JEE Main and All India Ranking
The process of compilation of the JEE Main result 2019 will be as follows
JEE Main Result compilation (First attempt)
NTA scores were calculated corresponding to the raw marks obtained by a candidate in each session as per the given formula. The calculated NTA scores for all the sessions were merged for declaration of result declared on January 19. The JEE Main result 2019 comprised of the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the first attempt held in January.
Compilation of JEE Main Result 2019 (Second attempt):
NTA will declare the scores corresponding to the raw marks obtained by a candidate in each session on April 30. The calculated NTA scores comprising the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt for all the sessions will be merged for the result declaration.
Compilation of Final JEE Main Result and Preparation of Merit List / Ranking:
The four NTA scores for each candidate for the first and second attempts will be merged for compilation of final result of JEE Main 2019 and preparation of overall Merit List / Ranking. The best of the two NTA scores will be considered for further for preparation of Merit List /Ranking as explained in the following example:
Example of JEE Main Ranking calculation
First Attempt – NTA Score
Second Attempt-NTA Score
Final NTA Score for compilation of result
(best of the two in Total)
Did not Appear
JEE Main Marks vs Percentile
With the new ranking system announced by NTA using the normalized scores of the candidates, the big question is how to calculate the JEE Main percentile for the marks obtained? The table below details the JEE Main marks vs percentile based on the trends of the past years. Candidates can estimate their JEE Main result 2019 using the table below.
Details of JEE Main Marks vs Percentile
JEE Main Marks
360 to 310
100 - 99.98724751
309 to 299
99.985572 - 99.9740296
298 to 288
99.97589128 - 99.96258028
287 to 278
99.96146328 - 99.94424276
277 to 268
99.94098483 - 99.91929629
267 to 258
99.91836545 - 99.89081262
257 to 248
99.88643768 - 99.84845946
247 to 238
99.84510844 - 99.79959043
237 to 228
99.79679791 - 99.73294238
227 to 218
99.73005678 - 99.65475193
217 to 208
99.64888765 - 99.55273201
207 to 198
99.54919482 - 99.43609792
197 to 188
99.4200875 - 99.28958392
187 to 178
99.26473052 - 99.07781811
177 to 168
99.06329703 - 98.85683701
167 to 158
98.82509541 - 98.55710695
157 to 148
98.53104347 - 98.20040957
147 to 138
98.14939961 - 97.75686494
137 to 128
97.69477799 - 97.17648701
127 to 118
97.13841571 - 96.41990133
117 to 108
96.35511496 - 95.49744019
107 to 98
95.42678954 - 94.40128456
97 to 88
94.19473145 - 92.74709113
87 to 78
92.61891464 - 90.64227869
77 to 68
90.42902355 - 87.34180397
67 to 58
87.34180397 - 82.68016383
57 to 48
81.92571907 - 75.39020758
47 to 38
74.13450619 - 64.11300382
37 to 28
62.88839244 - 49.28762915
27 to 18
49.01228707 - 33.08815042
17 to 1
31.32570046 - 9.077538863
The exam conducting body will release the JEE Main 2019 April attempt answer key and OMR sheets after the exam is conducted. Using these items, the candidates will be able to calculate their probable scores and in turn assess their chances of getting admission to an institute or course of their choice. When calculating probable scores, the candidates must strictly follow the marking scheme of the exam as outlined in JEE Main 2019 exam pattern.
For every correct answer, the candidate will be awarded 4 marks
In case of incorrect attempt, 1 mark will be deducted
Using the OMR sheets, the candidate will be able to calculate the total number of correct and incorrect attempts. Next calculate the total positive and negative marks. The total score can be found by deducting the total negative marks from the total positive marks.
Total positive marks = (Total correct attempts) x 4
Total negative marks = (Total incorrect attempts) x 1
Total JEE Main Score = Total positive marks – Total negative marks
In case of a tie when two or more candidates obtain equal Total NTA Score in JEE Main 2019, inter-se merit of such candidates shall be determined in following order:
Important information included on the result is the qualifying cutoff of JEE Main 2019. Only those candidates who meet or score above the JEE Main 2019 qualifying cutoff will be eligible to appear in JEE Advanced 2019, or else they will be disqualified. Please note that the cutoff of JEE Main is prepared based on factors like number of applicants, availability of seats, and also past trends.The qualifying JEE Main cutoff 2019 is available, so candidates may refer the cutoffs of previous years’ to get an idea how much they might need to score.JEE Main 2019 Cutoff Score
Common Merit List
JEE Main 2018 Qualifying Cutoff
Common Rank List
As the table above shows, last year a total of 231024 candidates qualified for JEE Advanced. Candidates must note that the figure is flexible, as in 2017 only 224000 had qualified in the exam.
JEE Main 2017 Qualifying Cutoff
NTA will prepare the rank list of JEE Main 2019 based on the four NTA scores.The scores for the first attempt as well as for the second attempt will be merged for compilation of result and preparation of overall Merit List / Rank list.Best of the two NTA scores will be considered for the candidates who will give both the attempts of January and of April.
Joint Seat Allocation Authority (JoSAA), the sole body responsible for joint seat allocation, releases the seat allotment result in the form of ranks only. Now many candidates who plan to appear in JEE Main 2019 might have a specific score in their mind that they are targeting. But how do these candidates know the corresponding rank for that score. One way of finding out the rank for a particular score is get in tough with candidates who have themselves appeared in the exam. But it is a tedious exercise, and cannot be adopted to find out the corresponding ranks for a whole range of scores. So, in a bid to make the candidates’ job a bit easier, we bring you JEE Main ranks vs marks. While the comparison is not full proof, they are closer to the real thing.
301 to 360
1 - 9
281 to 300
10 - 83
261 to 280
84 - 244
241 to 260
245 - 706
221 to 240
707 - 1755
201 to 220
1756 - 4163
181 to 200
4164 - 8997
161 to 180
8998 - 18371
141 to 160
18372 - 35928
121 to 140
35929 - 67649
101 to 120
67651 - 125722
81 to 100
125723 - 237034
61 to 80
237035 - 463443
41 to 60
463444 - 844544
21 to 40
844546 - 1093113
1 to 20
1093115 - 1121966
What is the difference between Percentage and Percentile score?
Many of us have made the mistake of assuming percentage and percentile to be the same thing, when in fact they are different. For example, one of the eligibility criteria for admission at the NITs, IIITs, and GFTIs is candidates must be placed inside the top 20 percentile of respective boards (10+2 exam) to be eligible for admission. Now unless the candidates knows what percentile means, there are chances mistakes may happen. That is why we have thought it prudent to explain the difference between the two terms.
Difference between percentage and percentile
Percentage = marks obtained / total marks x 100
Percentile = 100 x Number of candidates in the group with aggregate marks less than that obtained by the candidate/ Total number of candidates in the group
For the purpose of admission, category-wise top 20 percentiles are accepted. This means the top 20 percentile list will be different for general, OBC, ST and PwD categories.
Take for example, if the total number of candidates who have registered in a particular board is 14111 and total number of candidates who appeared in the entrance exam is 13991, then, then the percentile will be calculated as:
Percentile of a student who has scored 50% marks in the Board where 2250 candidates have scored below him
Percentile score for 50% marks in the Board will be calculated as 2250 x 100/ 13991 = 16.081
Subject-combination for calculating top 20 percentile
The subject combination for calculating top 20 percentile will vary depending on whether the candidate wants to get admission in B.Tech courses or B.Arch courses.
A. Subject-combination for B.Tech courses
For calculating top 20 percentile for candidates belonging to this category, the following five subject combination will be accepted.
Any one of (Chemistry, Biology, Biotechnology, Technical Vocational Subject
Any other subject
Note: In a candidate has studies 6 subjects in the qualifying exam, in such cases the better of the fifth or sixth will be considered.
B. Subject combination for B.Arch/B.Plan
The following subject combination will be considered for calculating the top 20 percentile for admission to B.Arch/B.Planning courses:
Any other four subjects.
JEE Main 2018 Statistics
No. of Boys
No. of Girls
Total Candidates Registered for Paper 1
Candidates Registered for Offline Exam
Candidates Registered for Online Exam
Candidates Appeared for Offline Exam
Candidates Appeared for Online Exam
Candidates Qualified for Appearing in JEE Advanced
Previous Year's JEE Main Seat Matrix
Total Number of Seats
Indian Institute of Information Technology (IIITs)
National Institute of Technology (NITs)
Government Funded Technical Institutes
FAQs on JEE Main 2019 Result
Q. How to know if qualified for JEE Advanced 2019 exam?
A. Candidates who got more than or equal to cut off (category wise) released by NTA will be qualified for the JEE Advanced exam 2019. Only the top 2,45,000 JEE Main 2019 qualified candidates will be eligible for JEE Advanced examination. You can check your cut off in your JEE Main 2019 score card.
Q. How to check eligibility for JEE Advanced 2019?
A. The followings are the eligibility to appear for JEE Advanced examination,
Q. How many students appeared in JEE Mains 2019?
A. There are 608440 candidates were appeared in the January session and similarly, there are totally 881096 candidates participated in the April session. 77% of students appeared in both the sessions of JEE Main 2019 examination i.e., 1147125 candidates.
Q. What will my JEE Main result in April contain?
A. The JEE Main result 2019 to be declared in April will give the percentile scores and the ranks obtained by the students. The ranks will be used as the basis for admissions.
Q. How will I know my best score? Will the April and January scores be given separately?
A. To allow candidates a clear idea, both the January and April scores will be mentioned and the rank will also be mentioned.
Q. How will the ranking be calculated for JEE Main 2019 considering both the attempts?
A. JEE Main 2019 ranks will be calculated on the basis of the final percentile that will be mentioned for each candidate. The best of the two scores will be used for candidates who have appeared in both the sessions while the score of the session appeared will be used for all others.
Q. Since percentile can be same in a session for two or more candidates, how will the ranks be awarded?
A. Well, the ranking will be as per the inter-se-merit guidelines which are discussed in detail in the article above. The ranks will be awarded as per the same.
Q. How can I know for which percentile I will get a seat?
A. This, unfortunately, is something that cannot be predicted just like that. Its better to use a rank predictor tool that uses past trends keeping your category in mind and then gives all those options.
Q. Will the JEE Advanced qualifying status be announced with the JEE Main 2019 result?
A. Yes, the cutoff marks, as well as JEE Advanced qualifying status, will be announced by NTA with the JEE Main result 2019. It must be noted that this is the cutoff to appear for JEE Advanced and not for admissions through JEE Main.
Q. Should I drop one year if I dont get the requisite percentile for admissions?
A. This is not advisable as statistics show very few candidates succeeding in their second attempt. It is more prudent to take admissions in colleges /universities other than NITs, IIITs or GFTIs. That way you won't waste one whole year. However, if you are strong-minded about the reattempt and willing to work very hard, you may also choose to do so.
Q. Can I ask for revaluation of the result of JEE Main 2019?
A. No, you cannot ask for revaluation. This is a computer-based test hence chances of malpractices are less and NTA does not entertain revaluation.
Q. I think I should have got more marks when I check the answer key but my result shows a lower percentile?/ Can I get clarity on this?
A. Actually, NTA will release your marks and percentile. To know the calculation behind it, you will require statistics on how many students attempted the test along with you which NTA does not release. So chances of clarity on this is practically nil.
JoSAA Seat Allocation 2019 - The result of JoSAA 2019 seat allocation for round 7 has been announ...
JoSAA 2019 - The authorities has started JoSAA 2019 counselling and seat allocation process. Know...
JEE Main Question Papers - NTA has released JEE Main 2019 question papers for both January and Ap...
JEE Main Application Form 2020 - NTA will release JEE Main 2020 application form in the first wee...
JEE Main Exam Dates 2020 - Candidates can check the exam dates of JEE Main 2020 to know the tenta...
Hey Aspirant as you have mentioned in your query that your rank is 61882 then I must tell you that on this rank it is not very likely for you to ge...
Hi Vaibhav as per your query you have asked that whether production and industrial engineering in NIT Kurukshetra a good option then I was tell you...
Hi Vineesh as per your query you have asked for the joining date of IIIT Trichupalli 2019 so I want to tell you that the academic calendar for the ...
Hey aspirant there is chances for you to participate in the cseb round of JEE Mains because this is a special round which is done for the fulfillme...
Hello aspirant ,
I'm sorry to inform you but according to previous year statistics you can not get any nits/iiits/gftis in special round as your ra...
Your JEE Main brochure has been successfully mailed to your registered email id .
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile