IIST B.Tech Application Form 2019
Saumya Vishnoi, 18 Jun 2019, #JEE Advanced
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IIST B.Tech Application Form 2019 - Indian Institute of Space Science and Technology has closed the application form of IIST B.Tech admission 2019. The application form were available from June 3 till June 17 up to 5:00 PM. Candidates who are applying for admission in IIST B.Tech are advised to read all the eligibility criteria. Candidates need to enter all the required details, pay the application fee and submit the IIST B.Tech 2019 application form in order to be considered for admission. The deadline to submit the IIST B.Tech application form 2019 was June 17. Check all the relevant details related to the application form of IIST B.Tech 2019 given below in the article.
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IIST B.Tech 2019 Application Form- Important Dates

Events

Dates

Online Registration and Filling-in of Branch Preferences


3 June 2019 10:00 AM


Closing of Online Registration


17 June 2019 11:00 AM


Publication of IIST Admission Rank List


19 June 2019 5:00 PM


Closing date for Filling-in of Branch Preferences


20 June 2019 12:00 PM


Seat Allotment/ Acceptance rounds


Starts on 21 June 2019 11:00 AM (First seat allocation round)

Ends on 23 July 2019 (Last seat acceptance round)



Information to keep ready before filling the IIST B.Tech Application Form 2019

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Candidates are advised to keep the following information ready before starting to fill the application form of IIST B.Tech 2019:

  • Valid email Id

  • Roll number of JEE Main 2019

  • Roll number of JEE Advanced 2019


Step-by-step Procedure to fill IIST B.Tech 2019 Application Form

Candidates aspiring to apply for IIST B.Tech admission 2019 can check the detailed step by step procedure to fill and submit the application form which is given below:

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Step 1- Registration:

The candidates will have to register using the following information:

  • JEE Advanced 2019 roll number

  • Date of birth.

Step 2-Filling of requisite details:

After the successful registration, the candidates will have to enter the required information to fill the IIST B.Tech Application Form 2019. Details like personal and academic information have to be entered. The following details have to be entered:

  • Name

  • Address

  • Contact number

  • Marks obtained in JEE Advanced

  • Marks obtained in JEE Main

Step 3- Application Fee Payment:

After reviewing all the filled details, candidates will have to pay a non-refundable amount of application fee. The payment has to be done in online mode through SBI-Collect. The amount of fee which has to be paid is given below:

S.No.

Categories

Gender

Amount (in INR)

1

General and OBC

Male

600

2

General and OBC

Female

300

3

All SC, ST & PD

Male & Female

300


Step 4- Choice filling:

After logging in using their IIST registration number and password, the candidates will have to select their choices of courses. The selection should be done in the order of preference. It is important for the candidates to select their preference otherwise they will not be able to participate in the admission process.

IIST B.Tech 2019 Admission Process

Indian Institute of Space Science and Technology will conduct IIST B.Tech Admission 2019 for admissions into the offered B.Tech courses in the institute. Since there is no entrance examination conducted, IIST B.Tech Admission will be done on the basis of JEE Advanced scores. The counselling of IIST B.Tech Admission 2019 will be conducted online and seats will be allotted on the basis of the rank list, preferences selected and availability of seats.

Programmes and Number of Seats offered by IIST B.Tech Admission 2019

S. No

Programme

Number of Seats

Duration

1

B.Tech. in Avionics

60

4 years

2

B.Tech. in Aerospace Engineering

60

4 years

3

Dual Degree (B.Tech. and M.S./M.Tech.)

20

5 years

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i passed class 12 in 2018 but given improvement in 2019 can i give jee advance and get admission in iit in 2020? is their any way so that i get admission in iit for btech?

Manidipa Kundu Student Expert 7th Dec, 2019
hi,
as you have passed 12th exam on 2018 , the passing year will considered as 2018. the improvement exam year is not consider for 12th passing year.
so for 2020 jee advance exam you are not eligible.
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lowering of vapour pressure of equimolar solution of glucose,sodium chloride and barium nitrate are in the order

prem meghani 7th Dec, 2019
Dear Aspirant,

Vant Hoff factor =i
For Barium nitrate,i=3,
2Ba+ No3-

For Nacl,i=2Na+ Cl-
i=2 vant Hoff factor

For glucose vant Hoff factor will be 1
I=1

So higher the vant Hoff factor higher will be the loweirng of vapour pressure.
So barium nitrate will have highest lowering in vapour pressure

Order will be barium nitrate>Nacl>glucose

Thanks
All the very best.
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Is HC Verma is sufficient for physics in JEE ADVANCED . R.D sharma and M.L khanna for MATHMATICS in JEE ADVANCED.....

Avishek Dutta 6th Dec, 2019
HC Verma and ML Khanna are good books for JEE but arenit sufficient.
For physics
1.Buy NCERT for understanding the syllabus and studying the basics
2.Buy any one of this
i.Arihant ii.Cengage
Now I woukd prefer Cengage for JEE advanced as the book thoroughly follows jee advanced patterns.
And now study and solve them .
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Saurabh Siddharth 6th Dec, 2019

Following is the list of few books for better preparation of JEE ADVANCE:

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Suggestions

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what is the cut off jee advance last 5 years

Halry Bhalodia 6th Dec, 2019

hello parag ,

cutoff for jee advance for last four years goes as :

  • Minimum Percentage of Marks in Each Subject  (A)
  • Minimum Percentage of Aggregate Marks  (B)

year  (category)      A                                   B

2019

CRL                            10.0                              25.0

OBC                           09.0                              22.5

SC                              05.0                              12.5

ST                               05.0                              12.5

2018

CRL                            10.0                              25.0

OBC                           09.0                              22.5

SC                              05.0                              12.5

ST                              05.0                              12.5

2017

CRL                            10.0                              35.0

OBC                           09.0                              31.5

SC                              05.0                              17.5

ST                              05.0                              17.5

2016

CRL                            10.0                              20.0

OBC                           09.0                              10.5

SC                              05.0                              10.5

ST                              05.0                              10.5

before this cutoff was based on subjects .


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